Latest TCS Aptitude Question SOLUTION: If x^y denotes x raised to the power y, find last two digits of (1941^3843) + (1961^4181)

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If x^y denotes x raised to the power y, find last two digits of (1941^3843) + (1961^4181)

Asked In TCS anuja hore (5 years ago)

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S.Sathiyachozhan  (5 years ago)

Concept 1: A number ending in 1

Last two digits of (…a1)^(…b) will be [Last digit of a*b]1

Ex 1.1 Last two digits of 1941^3843 = [Last digit of 4*3]1 = [Last digit of 12]1 = 21

Ex 1.2 Last two digits of 1961^4181 = [Last digit of 6*1]1 = [Last digit of 6]1 = 61

Ans is 21+61=82

Is this solution Helpfull? Yes (8) | No (1)  

  (5 years ago)

last digit in each number is 1,
so for the first number last two digits:21
last two digits for second number:61
ans:82

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ankit  (5 years ago)

base last two digits ^power unit digit + base last two digits ^power unit digit=41^3 +61^1=21

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Rounak Surana  (5 years ago)

Multiply 4 from 1st number to 3 in the power, which will give 12. Taking 2 from 12 and 1 is already present at units place in 1941; hence this gives 21.
Multiply 6 from 2nd number to 1 in the power, which will give 6. Taking 6 from 6 and 1 is already present at units place in 4181; hence this gives 61.
Now 21+61=82. Hence the last 2 digits will be 82.

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Sambit Koley  (5 years ago)

47 .
find the relation of multiplication in a series format, the same two last 2 digits will return every time.
the last 2 digits of 1st term should be 64 and of the second term is 83. hence it is 47.

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praneetha  (5 years ago)

41^3+61^1=21

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rishabh kumar  (5 years ago)

divide the power by 4 then put remainder as power and solve it now, multiple only 2 no. upto power

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