Latest TCS Aptitude Question SOLUTION: In the IT department of backrub, the administrator password is changed every month. The team of administrators, spread across the globe, receive an 8 digit number via email. This n

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In the IT department of backrub, the administrator password is changed every month. The team of administrators, spread across the globe, receive an 8 digit number via email. This number is to be prefixed with a single digit number and suffixed with a single digit number to get the actual password. The password is divisible by 11 and 8. If the team received 65351364 this month, then which of the following pairs give prefix and suffix respectively.
a. 8, 9
b. 7, 8
c. 3, 4

Asked In TCS Dilipan M (5 years ago)

Unsolved Read Solution (9)

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KUMAR UMESH  (5 years ago)

b is the answer

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Sindhu  (5 years ago)

1. Apply divisibility rule of 8
2. In the given options only b and c contains even suffix number
3. Therefore 65351364 will become 653513648 (in case of opt b) or 653513644 (in case of opt c)
4. consider opt b and apply divisibility rule of 11, it satisifies the rule hence the answer.

ANS - OPTION B

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monica  (5 years ago)

it could be option c) 3,4 because lcm of 11 and 8 is 88 the number must be divisible by 88 we have to use trial and error method to solve this question. only option c can satisfy

Is this solution Helpfull? Yes (1) | No (1)  

riya garg  (5 years ago)

for divisibility by 8, last 3 digits must be divisible by 8. By putting 65351364's last 2 digits 64 options suffix: 64 with 9, 64 with 8, 64 with 4, we get that 648 is divisible by 8.Thus (b) ans

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Anil Singh Tomar  (4 years ago)

The password would be 8653513649

8653513649 ÷ 11 = 786683059

8653513649 ÷  8 = 1081689206 Remainder 1

⇒ Number cannot be divisible by 8


Option b)

The password would be 7653513648

7653513648 ÷ 11 = 695773968

7653513648 ÷  8 = 956689206

⇒ Number is both divisible by 8 and 11


Option c)

The password would be 3653513644

3653513644 ÷ 11 = 332137604

3653513644 ÷  8 = 456689205 Remainder 4

⇒ Number cannot be divisible by 8


Option d)

The password would be 2653513647

2653513647 ÷ 11 = 241228513 Remainder 4

2653513647 ÷  8 = 331689205 Remainder 7

⇒ Number cannot be divisible by 8 and 11


Answer: (b) 7, 8

Read more on Brainly.in - https://brainly.in/question/6617045#readmore

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sambit das  (5 years ago)

b. 763513648/11

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Mounika Dasari  (5 years ago)

b is the answer

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ratnaraj  (5 years ago)

b is the anawers

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Rishika Singh  (9 Months ago)

7,8

8 is divided by last 2 digits but 9 and 4 is not

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