Latest tcs Aptitude Question SOLUTION: Q1. 1 red flag, 3 white flags and 2 blue flags are arranged in a line such that: I. No two adjacent flags are of the same colour II. The flags at the ends are of 2 different colour

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(#M40165518) TCS Numerical Ability question permutations and combinations Keep an EYE

Q1. 1 red flag, 3 white flags and 2 blue flags are arranged in a line
such that:
I. No two adjacent flags are of the same colour
II. The flags at the ends are of 2 different colours.
In how many different ways the flags be arranged?

Asked In tcs shrija (5 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (23)   (7) Submit Your Solution Permutation and Combination

Read Solution (5) :

anurag  (5 years ago)

Case 1:

W_W_W_

Case 2:

_W_W_W


we have 3 slots free where we have to arrange 3 flags.
3 flags can be arranged in 3! ways.
out of 3 flags, two are blue (identical).
Taking care of the 2 indistinguishable choices, we get, 3!/2! ways per case.

Since there are 2 cases, we get 2*3!/2!

Is this solution Helpfull? Yes (14) | No (3)  

Meera  (4 years ago)

Red flags are represented by R

White flags are represented by W

Blue flags are represented by B

And vacant spaces are represented by _

As No 2 adjacent flags are of the same colour, these are the 2 possible arrangements-

1. W_W_W_

OR

2. _W_W_W

Now, 1 red flag and 2 blue flags have to be arranged in these vacant places.

Hence, these 3 flags can be arranged in 3!/2! ways = 3 ways { RBB, BRB, BBR}

If we consider the 1st possible arrangement, then also these 3 flags can be arranged in 3 ways and this is applicable to the 2nd possible arrangement also.

So, Total number of ways = 3 + 3 ways

= 6 ways

Is this solution Helpfull? Yes (4) | No (1)  

Snehal  (5 years ago)

Answer is 36.. Because No two adjacent flags are of the same color..so assume 1 arrangement as B W B W R W.. so to arrange 2 blue balls,ways are 2!.. to arrange 3 white balls,ways are 3!.. & to arrange 1 red ball,ways are 1!.. & also , we are not confirm about which ball should come first, so again there are 3 ways. So,total = 2!*3!*1! * 3 = 36

Is this solution Helpfull? Yes (2) | No (7)  

ganesh babu  (4 years ago)

WBWBWR
WBWRWB
WRWBWB
BWBWRW
BWRWBW
RWBWBW
WBRWBW
WRBWBW
WBWBRW
WBWRBW
10 WAYS

Is this solution Helpfull? Yes (1) | No (6)  

Anusha  (4 years ago)

6 ways is the answer

Is this solution Helpfull? Yes (1) | No (2)  

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