Latest Infosys Aptitude Question SOLUTION: If (HE)^H=SHE, where the alphabets take the values from (0-9) & all the alphabets are single digit then find the value of (S+H+E)?

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If (HE)^H=SHE, where the alphabets take the values from (0-9) & all the alphabets are single digit then find the value of (S+H+E)?

Asked In Infosys palingi mukesh (5 years ago)

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Read Solution (14) :

Subbarao  (5 years ago)

25^2 = 625
6+2+5 = 13

Is this solution Helpfull? Yes (17) | No (2)  

Amal  (5 years ago)

We need to get a three digit number and the last two digits should be equal to the number whose power is taken. Use trial and error method. We know that if we take powers of numbers ending with 5 we should get 5 as the units place digit. Then we can get HE =25 . 25^2=625. so S+H+E = 6+2+5=13.

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kalaiyarasi periyasami  (5 years ago)

please show me ans for its

Is this solution Helpfull? Yes (3) | No   

Swati karemore  (5 years ago)

Given that we can take value from 0-9
Then most of the possibilities will come
1. If we take H=1 nd E=2 then
(9×2)^2=324
So. 3+2+4= 9 ...

Is this solution Helpfull? Yes (2) | No (12)  

sameera nallamalli  (5 years ago)

25^2 =625
6+2+5=13

Is this solution Helpfull? Yes (2) | No (1)  

kavitha sri  (5 years ago)

Let H=2
(2_)^2 = _2_. The only possibility is E=5
(25)^2 = 625

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AKKARAPALLI SANJEEV REDDY  (5 years ago)

(HE)^H=SHE ------> 25^2=625; ( because of H&E values are same in this possibility)
S+H+E ------> 6+2+5=13; (Since the values are S=6 , H=2 , E=5 )

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Chandar R  (5 years ago)

(25)^2 = 625
So 2+5+6=13

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Sowmya  (5 years ago)

(6)^2=6x2x3 =>36=36
6+2+3=11

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G.Chaithra  (5 years ago)

(HE)^H=SHE
let us assign the value H=2 and E=3
Then, (2*3)^2=36.
Equating by substituting the values of(HE)^H=36'
36=s(2)(3)
value ofs willbe 6.
checking the above equation by substituting the values of SHE=(6)(2)(3)=36
hence the values are S=6,h=2,E=3.
therefore S+H+E=6+2+3=11.

Is this solution Helpfull? Yes (1) | No (2)  

Puneet Gupta  (5 years ago)

6+2+5=13
h=2
e=5
s=6

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rannithkumar  (5 years ago)

(HE)^H=SHE
(25)^2=625

so;
H=2; E=5; S=6;

6+2+5=13

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Muthu Raj  (5 years ago)

arrange A-J(0-9)
likewise K-L(0-9) and U-Z(0-5)
the code is S=8,H=7,E=4 so 8+7+4=19 or (HE)^H must be in the range 21 to 29 so that result must be less then 999 (3 digit ,as SHE) .
so as per rule sol is (25)^2=625.
so S+H+E=6+2+5=13 ANS

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jnv somayajulu  (5 years ago)

25*25=625
6+2+5=13

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