Latest TCS Aptitude Question SOLUTION: 21. In a group of 5 families, every family has a certain number of children, such that the number of children forms an arthmetic progression with a common difference of one, starti

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(#M40166223) TCS General Ability question Keep an EYE

21. In a group of 5 families, every family has a certain number of children, such that the number of children forms an arthmetic progression with a common difference of one, starting with two children in the first family. Despite the objection of their parents every child in a family has three times as many pets to look after as the number of offspring in the family. What is the total number of pets in the entire group of five families.

Asked In TCS Ggopinath (4 years ago)

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Reddi Anitha Rani  (4 years ago)

answer is 270.
Number of children= 2,3,4,5,6
no. of pets=2*2+ 3*3 + 4*4 + 5*5 +6*6 =90
it is given that 3 times as many pets = 90*3 = 270.

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prachi pragyan das  (4 years ago)

I think answer is 60

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nikhitha  (4 years ago)

As the number of children are in arithmetic progression starting with 2, the five families have 2, 3, 4, 5, 6 kids respectively.
As each children has kept the pets equal to the number of kids in the family, Each family has n^2 pets.
So total = 2^2+3^2+4^2 +5^2 +6^2 = 90

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