Latest TCS Aptitude Question SOLUTION: In the diagram below, the areas of the triangles are as follows: A1=1024, A2=1016, A3=1057. What is the area of A4? a. 1032 b. 1036 c. 1020 d. 1065

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In the diagram below, the areas of the triangles are as follows: A1=1024, A2=1016, A3=1057. What is the area of A4?

















a. 1032

b. 1036

c. 1020

d. 1065

Asked In TCS Ggopinath (4 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

Roopa  (4 years ago)

A1=a.h1/2,A3=a.h2/2,h1=h2=b;
h2=b-h1;
1024=a.h1/2.1057=a.(b-h1)/2;
1057=(ab/2)-(ah1/2);
ab=4162;
the total area of the reactangle is A=a.b, A=4162;
A4=A-(A1+A2+A3)
A4=1065

Is this solution Helpfull? Yes (2) | No (5)  

Mohammed Mubeena  (4 years ago)

consider area of 1st triangle = A1 = (1/2)*b*h1;
i,e 1024 = i/2*bh1;
bh1 = 2048;-----(1)
Area of 3rd triangle = A3 = (1/2) *b*h2;
bh2 = 2114;-----(2)
Now, let Height of 4th triangle be H
where, H = h1 + h2;
therefore, h2 = H - h1;
from (2) we get b(H-h1) = 2114;
bH - bh1 = 2114
bH = 2114 - bh1
bH = 2114 - 2048 from(1)
Therefore total area => bH = 4162
now A4 = Total area - (A1+ A2 + A3)
A4 = 4162 - 3097
A4 = 1065

Is this solution Helpfull? Yes (2) | No (1)  

Pavani  (2 years ago)

Where is the diagram n where we get this?

Is this solution Helpfull? Yes (1) | No   

James mathews  (2 years ago)

Diagram is not visible

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