Latest TCS Aptitude Question SOLUTION: We have two cubes. the sum of the two cubes is 25. The sum of a side length of one cube and a side length of the other is 4. What is the sum of the total surface areas of the two c

• Placement Papers
• /
• TCS
• /
• Category

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40166246) TCS Category question Keep an EYE

We have two cubes. the sum of the two cubes is 25. The sum of a side length of one cube and a side length of the other is 4. What is the sum of the total surface areas of the two cubes?

Asked In TCS Ggopinath (4 years ago)

Unsolved Read Solution (2)

Is this Puzzle helpful?   (8)   (1) Submit Your Solution

Read Solution (2) :

keerthana  (4 years ago)

Let a side of one cube be X and one side of another cube be Y.
Given X+Y=4
Surface area of cube = 6s^2
6X^2 = 6Y^2 by sloving we get Y=2 [ since X=4-Y]
We also get X=2
The sum of total surface areas of the two cubes = 48

Is this solution Helpfull? Yes | No (2)  

eswar  (4 years ago)

'a' is the side of one cube and 'b' is the side of another one.
Sum of Vol of two cubes (a^3+b^3) =25.
Sum of sides of two cubes (a+b) =4.
(a+b)^3= a^3 + b^3 + 3ab(a+b).
From above eqn we got, ab =(39/12).
Then w.k.t (a+b) ^2= a^2 + b^2 +2*ab.
Substitute ab =(39/12) and (a+b) =4 as we know.
Finally we got (a^2 + b^2) value. - - - eqn 1
Surface area of cube is 6*(a^2 + b^2).
Put eqn 1 in above so that we get 48.
Thank you...

Is this solution Helpfull? Yes | No (2)  

Please Login to Read Solution.