Latest Accenture Aptitude Question SOLUTION: Three cars leave A for B in equal time intervals. They reach B simultaneously and then leave for Point C which is 240 km away from B. The first car arrives at C an hour after the

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Three cars leave A for B in equal time intervals. They reach B simultaneously and then leave for Point C which is 240 km away from B. The first car arrives at C an hour after the second car. The third car, having reached C, immediately turns back and heads towards B. The first and the third car meet a point that is 80 km away from C. What is the difference between the speed of the first and the third car?
A)80 kmph B)20 kmph C)60 kmph D)40 kmph

Asked In Accenture Devendra Marghade (4 years ago)

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Read Solution (1) :

  (3 years ago)

Let V1, V2 and V3 be the speeds of the cars.

ABV1 - ABV2 = ABV2 - ABV3
240V1 - 240V2 = 1
V3 = 2V1
Condition I states that the cars leave in equal intervals of time and arrive at the same time. Or, the difference in the time taken between cars 1 and 2 should be equal to the time taken between cars 2 and 3.

We get ABV1 - ABV2 = ABV2 - ABV3
As the second car arrived at C an hour earlier than the first, we get a second equation
240V1 - 240V2 = 1
The third car covered 240 + 80 kms when the first one covered 240 – 80 kms. Therefore, 320V3 = 160V1
This gives us V3 = 2V1
From condition 1, we have ABV1 - ABV2 = ABV2 - ABV3
Substituting V3 = 2V1, this gives us ABV1 - ABV2 = ABV2 - AB2V1
or 3AB2V1 = 2ABV2 or V2 = 4V13
Solving 240V1 - 240V2 = 1 , we get 60V1 = 1 or V1 = 60 kmph
=> V2 = 80 kmph and V3 = 120 kmph

Hence, the answer is 60 kmph

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