Latest Hexaware Aptitude Question SOLUTION: A, B, C and D divided Rs. 44,352/- among themselves A took (3/8)th of the money, B took (1/6)th of the remaining amount and the rest was divided among C and D in the ratio of 3:4 r

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(#M40166815) HEXAWARE Numerical Ability question Keep an EYE

A, B, C and D divided Rs. 44,352/- among themselves A took (3/8)th of the money, B took (1/6)th of the remaining amount and the rest was divided among C and D in the ratio of 3:4 respectively. How much did C get as his share?
A)Rs. 13,200/- B)Rs. 16,632/- C)Rs. 10,300/- D)Rs. 8,700/- E)Rs. 9,900/-

Asked In Hexaware Devendra Marghade (4 years ago)

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Sushmitha K  (4 years ago)

ANS:Rs.9,900
amount taken by A=3/8*44352=16632
remaining amount=44352-16632=27720
amount taken by B=1/6*27720=4620
remaining amount=27720-4620=23100
c gets 3/7 of the share is Rs.23100=3/7*23100=9900

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Aakansha Parihar  (3 years ago)

3/7*5/6*5/8*44352=9900 .ans

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Chandramohan  (3 years ago)

The answer is 8700

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Billal Hossain  (3 years ago)

A took = 44352*3/8=16632
Remaining amount= 44352-16632=27720
B took = 27720*1/6=4620
Threfore, Rest amount = 27720-4620=23100
suppose, C get as share = 3x and D get as share = 4x
according to question, 3x+4x=23100
or, 7x=23100
therefore, x=23100/7=3300
So, C get as his share = 3*3300=9900(ans)
In this case, My option is (E)

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sivakumar  (1 year ago)

total amt=44,352
remaining after, a=44,352/8*5=27,720
remaining after, b=27,720/6*5=23,100
c share =23,100/7*4=9,900

ans is E) 9,900

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