Latest TCS Aptitude Question SOLUTION: George can do some work in 8 hours. Paul can do some work in 10 hours while Hari can do the same work in 12 hours. All three of them start working at 9.00 am. While George stops wo

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(#M40167170) TCS General Ability question Keep an EYE

George can do some work in 8 hours. Paul can do some work in 10 hours while Hari can do the same
work in 12 hours. All three of them start working at 9.00 am. While George stops work at 11.00 am
and the remaining two complete the work. Approximately at what time the work be finished?
(a) 11.30 am (b) 12.30 pm
(c) 1 pm (d) 12 noon

Asked In TCS kamala (1 Month ago)

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Jyothi Reddy  (6 Days ago)

At first George =G,Paul=P, Hari=H
G=1/8,P=1/10,H=1/12
LCM(8,10,12)=120
So that G=8/120=15units of per hour
Like wise P=12u/h
H=10u/h
Then
At 8:00 to 11:00
2 hours =2*10+12+15
=37/120(23/60)
1-37/120=23/60
Then after 11:00 G leaves so remaining work is 23
So
1/10+1/12=5uld+6uld=11 uld
So they need 2 hours
1pm

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