Latest Others Aptitude Question SOLUTION: Two candles of the same length are made of different materials so that one burns out completely at a uniform rate in 3 hours while the other burns out in 4 hours. At what time (i

• Placement Papers
• /
• Others

Others Question Papers:

(#M40017807) OTHERS question Keep an EYE

Two candles of the same length are made of different materials so that one burns out completely at a uniform rate in 3 hours while the other burns out in 4 hours. At what time (in PM) should both candles be lit so that at 9 PM one candle stub is twice the length of the other?

Asked In Others Paningapalli Venkata Rama Devi (11 years ago)

Unsolved Read Solution (3)

Is this Puzzle helpful?   (2)   (3) Submit Your Solution

Read Solution (3) :

anjul meid  (11 years ago)

6:36 pm....let rate of burning of 1st and 2 nd candles be x and y respectively...den length of both candles is 3x and 4y...and as dese are equal we have 3x = 4y.....now let after t hour after burning the event described in the question takes place so after t hours stub of 1st candle=tx and length of other candle after t time= 4y-ty......and according to the question tx= 2*(4y-ty) =>tx= 8y-2ty....=>t(x+2y)=8y=>t=8y/(x+2y)...putting values from above equation...we get t=2.4 hour or 2 hours and 24 minutes so we lit both candles at 6:36 pm

Is this solution Helpfull? Yes (2) | No (1)  

Garima  (11 years ago)

suppose length of each candle is 12 units
and first candle burns 4 units in 1 hr and other candle burns 3 units in 1 hr, and suppose one candle stub is twice the length of the other after x hrs,then
(12-3x)/(12-4x)=2
x= 12/5 hrs = 2 hrs 24 mins

so both candles should be lit at 6:36 PM.

Is this solution Helpfull? Yes (1) | No (1)  

sumit jindal  (11 years ago)

(x+1-1)^45+52
binomial implies only -1^45 is the remainder from the first term that is -1
so net remainder = -1+52=51

Is this solution Helpfull? Yes | No (2)  

Please Login to Read Solution.