Latest self Aptitude Question SOLUTION: A1B2C3=FH D1E2F3=OQ G1H2I3=??

• Placement Papers
• /
• self

self Question Papers:

(#M40018261) SELF question Keep an EYE

A1B2C3=FH
D1E2F3=OQ
G1H2I3=??

Devendra Marghade (11 years ago)

Unsolved Read Solution (4)

Is this Puzzle helpful?   (1)   (0) Submit Your Solution

Read Solution (4) :

lakshmi chaitanya  (11 years ago)

or simply
fh=6,8
oq=15,17
f~o=h~q=9
so 15+9,17+9=24,26=x,z

Is this solution Helpfull? Yes (2) | No   

gayathri  (11 years ago)

G1H2I3=XZ

Is this solution Helpfull? Yes (1) | No   

lakshmi chaitanya  (11 years ago)

a=1,b=2,c=3...,z=26

abc=fh-> 1 2 3= 6(1+2+3) 8(digit1+2)
def=oq-> 4 5 6=15(4+5+6) 17(digit1+2)
ghi=xz-> 7 8 9=24(7+8+9) 26(digit1+2)
so g1h2i3=xz

Is this solution Helpfull? Yes (1) | No   

Adarsha Upadhya  (11 years ago)

A1B2C3=FH A1=1X1=1;B2=2X2=4;C3=3X3=9::A1+B2+C3=14:::FH=6+8=14----diff b/w F&H is 2

D1E2F3=OQ D1=4X1=4;E2=5X2=10;F3=6X3=18::D1+E2+F3=32::OQ=15+17=32---diff b/w O&Q is 2

G1H2I3=?? G1=7X1=7;H2=8X2=16;I3=9X3=27::G1+H2+I3=50:: in order to make LHS 50 possible combination with difference 2 is XZ=24+26;

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.