Latest Elitmus Aptitude Question SOLUTION: How many 4 digits no are divisible by 25 among the digits 0,1,2,3,4,5,6,7 with no digit being repeated

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(#M40018452) ELITMUS Numerical Ability question Permutation and combination Keep an EYE

How many 4 digits no are divisible by 25 among the digits 0,1,2,3,4,5,6,7 with no digit being repeated

Asked In Elitmus Sumit Rawal (11 years ago)

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DIKSHA RANGNANI  (11 years ago)

80
last 2 digit can be 25 , 50 and 75
so for _ _ 2 5 arrangement can be 5*5 because 0 cannot come on first position 25
simillarly for _ _ 7 5 25
and for _ _ 5 0 6 *5 = 30
so 25+25+30=80

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farjana sayyed  (10 years ago)

i think it is 84,,
_ _ 25
or
_ _ 50

or
_ _ 75

case 1: _ _ 25
possibility for 2st digit=6
possibility for 1st digit=4(except 0)
6*4=24
same for _ _ 75=24
case 2: _ _ 50
possibility for 2nd digit=6
possibility for 1st digit=6
6*6=36
total=2(24)+36=84

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MD SHOAIB  (10 years ago)

--25
--50
--75
case 1:--25
when 1 is at thousand place no of ways is 5
similarly 2 is not considered as the digits will be repeated
when 3,4,6,7 is used again there i 5 ways so total 25 ways
case 2:--50
there is 30 ways
case 3:--75
there is 25 way so total ways is 25+25+30=80

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chakrapni  (11 years ago)

5! 4! 2 because when the number has to be divisible by 25 last two numbers must be 5 0 so last two digits are 5 and 0 so remaining 5 num are placed in 5! ways and in second digit in 4! ways.

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DIKSHA RANGNANI  (11 years ago)

7c3 * 3! * 2
am i rite?

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