Latest Elitmus Aptitude Question SOLUTION: In an opinion poll 78% of those asked were in the favour of atleast one of the three sports persons to be included in the commonwealth organizing commitee Saina, Dhoni and Anand. 5

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(#M40018476) ELITMUS Numerical Ability question Percentage Keep an EYE

In an opinion poll 78% of those asked were in the favour of atleast one of the three sports persons to be included in the commonwealth organizing commitee Saina, Dhoni and Anand. 50% of those asked favoured Saina, 30% favoured Dhoni 20% favored Anand.If 5% of those asked favoured all of them,what percentage of those asked favoured atleast one person ??
Options
A)61
B)56
C)51
D)22

Asked In Elitmus Sumit Rawal (10 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

Saiyam Behl  (10 years ago)

Let x% be in favour of A and B
y% be in favour of B and C
z % be in favour of A and C

=> 78 - 5 - (x + y + z) = (50-5-x-z) + (30-5-x-y) + (20-5-y-z)
=> (x + y + z) = 12%

=> (78 - (x+y+z)-5) = 61%

Is this solution Helpfull? Yes (35) | No (4)  

jaspreet  (10 years ago)

comes out to be 61 for exactly one.

Is this solution Helpfull? Yes (7) | No   

PRATIM JANA  (8 years ago)

opinion poll 78%
let X% for A&B
Y% for B&C
Z% for C&A
78-5-(X+Y+Z)=(50-5-X-Z) + (30-5-x-y) + (20-5-y-z)
=> 73 -X-Y-Z=100-15-2X-2Y-2Z
=> (X+Y+Z)=12%
78-5-12=61% ans

Is this solution Helpfull? Yes (7) | No   

Sneha Agarwal  (10 years ago)

61 for exactly one person

Is this solution Helpfull? Yes (3) | No (1)  

nishanth  (10 years ago)

let total members be 100
78% of 100 is 78

raina=50%of 78=39
dhoni=30%of 78~23
anand=20%of 78~16
all 5%of 78 all=3.4~3

use venn diagram dude

so atleast one person=only raina+only dhoni+only anand+raina&&dhoni&&anand
=raina-all+dhoni-all+anand-all+all
=39-3+23-3+16-3
=36+20+13=69
69*100/78=88.8

Is this solution Helpfull? Yes (2) | No (13)  

shashank singh  (8 years ago)

61%

5% were in favour of all
Let x% be in favour of A and B
y% be in favour of B and C
z % be in favour of A and C

=> 78 + 5 - (x + y + z) = (50+5-x-z) + (30+5-x-y) + (20+5-y-z)
=> (x + y + z) = 32%

=> (78 - (x+y+z)+5) = 51% favoured exactly one.

Is this solution Helpfull? Yes (1) | No   

Sumit Rawal  (10 years ago)

In the last line it is exactly one person by this the answer is 56

Is this solution Helpfull? Yes | No (11)  

khushbu singh  (10 years ago)

will u pls explain the answer....mr. sumit

Is this solution Helpfull? Yes | No (3)  

shweta sharma  (10 years ago)

@sumit pls explain d answer?

Is this solution Helpfull? Yes | No (1)  

farjana sayyed  (10 years ago)

could anyone tell me the another way of solving this question?
I am not getting this ways

Is this solution Helpfull? Yes | No (1)  

roshan  (8 years ago)

Let x% be in favour of A and B
y% be in favour of B and C
z % be in favour of A and C

=> 78 - 5 - (x + y + z) = (50-5-x-z) + (30-5-x-y) + (20-5-y-z)
=> (x + y + z) = 12%

=> (78 - (x+y+z)-5) = 61%
Read more at http://www.m4maths.com/18476-In-an-opinion-poll-78-of-those-asked-were-in-the-favour-of-atleast-one-of-the-three-sports-persons.html#2cH2IsUPbhIZsrWs.99

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Vamsi  (1 year ago)

Abxjdjdheisisudh

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