Latest Elitmus Aptitude Question SOLUTION: how many 4 digits number can be formed by using set 0,1,2,3,4,5,6,7 which is divisible by 25 and repetition of digit is not allowed..

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(#M40018550) ELITMUS Numerical Ability question permutation Keep an EYE

how many 4 digits number can be formed by using set 0,1,2,3,4,5,6,7 which is divisible by 25 and repetition of digit is not allowed..

Asked In Elitmus pushprndra (11 years ago)

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rizwanur rahman  (11 years ago)

if 25 is the last two numbers then the first number can be selected in 5 ways (1,3,4,6,7) and the second number can be selected in 5 ways (4 numbers from the set of numbers and 0 included . so total 5) so the total number of ways are 5*5=25....(1)
similarly if 75 is the last two numbers then there 25 ways possible.....(2)
if 50 is the last two numbers then the first number can be selected in 6 ways and the second number in 5 ways. so total wys = 6*5 =30 .....(3)
hence the total possible ways are 25+25+30 = 80

Is this solution Helpfull? Yes (30) | No (3)  

Sumit Rawal  (11 years ago)

The correct answer is 80

Is this solution Helpfull? Yes (8) | No   

Yogesh Shukla  (11 years ago)

At the last two places 25, 50, 75 are possible.
100th place can be filled by (8-2)= 6 different numbers.
1000th place can have (8-3-1)= 4 because 0 can't be at 1000th place.
total numbers will be = 4*6*3= 72

Is this solution Helpfull? Yes (1) | No (14)  

aditya  (11 years ago)

I am also getting 72 Answer
what is correct answer..??

Is this solution Helpfull? Yes | No (5)  

SACHIN AGGARWAL  (11 years ago)

72 is the correct answer

Is this solution Helpfull? Yes | No (5)  

Amit Kumar Singh  (7 years ago)

__ __ 2 5= 5*5

__ __ 5 0=6*5

__ __ 7 5 = 5*5

total =25+30+25= 80

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