Latest Elitmus Aptitude Question SOLUTION: 100^x (log 4 base x - log root2 base x )..Find Min and max values. a. 0,infinity b. -infinity, infinity c. infinity,-infinity d.none

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(#M40019179) ELITMUS question Keep an EYE

100^x (log 4 base x - log root2 base x )..Find Min and max values.
a. 0,infinity b. -infinity, infinity c. infinity,-infinity d.none

Asked In Elitmus Archita Mitra (10 years ago)

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nishanth  (10 years ago)

value would always be positive value as log4basex-logroot2basex cant be negative
so answer would be 0 to infinity

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babu rao ganpat rao apte  (10 years ago)

the answer will be (c).....
check the value for x=.5 it comes -ve

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deepak srivastava  (10 years ago)

0 and infinity

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venkatesh  (10 years ago)

100^x(log4 base x - log root2 base x )
(log4 base x - log root2 base x ) = (2log2 base x - (1/2)log2 base x )
= (3/2)(log2 base x)
= 3/(2 * logx base 2)
so resultent = ((100^x)*3)/(2*logx base 2)
if x =1 then resultent = ((100^x)*3)/0 = infinity
so max value is infinity

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