Latest Elitmus Aptitude Question SOLUTION: question was like:: there is side of a hexagon given(6 root 2)... it was said that joining the mid points of each side another hexagon was created... what was the difference betw

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(#M40019747) ELITMUS Logical Reasoning question 4 augast Keep an EYE

question was like:: there is side of a hexagon given(6 root 2)... it was said that joining the mid points of each side another hexagon was created... what was the difference between the areas of two hexagon(express as %)....dont remember the option...i marked 25 percent as answer....

Asked In Elitmus babu rao ganpat rao apte (10 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

Raghav  (10 years ago)

AREA outer hexagon =6*((root 3)/4)*(6 root 2)2
firstly we will calculate inner hexagon side=root of ((3 root 2)2+ (3 root2)2)=6
area of inner hexagon=6*((root 3)/4)*(6)2
diiference b/w the areas of two hexagon(express as %)=((AREA-area)*100)/AREA %
=50 %

Is this solution Helpfull? Yes (11) | No (13)  

raju kumar  (10 years ago)

25% is right answer
difference of area is 27 squrt3
and total area is 108squrt3
hence 25%

Is this solution Helpfull? Yes (8) | No (6)  

Govind Kishore  (10 years ago)

chopped the hexagon into 24 equal triangle of which 18 compose the smaller hexagon, making the ratio of the areas 18/24 = 3/4, with 1/4 of the original area cut off. (First join the midpoints to the center of the hexagon to obtain 6 equilateral triangles. In each of these, join the center with the vertices. On the right you see the minimal configuration that explains the solution.

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Pratyush  (10 years ago)

Area of big hexagon is (12roo3/8)a^2
Area of small Hexagon is (9root3/8)a^2
so diff. is 25%

Is this solution Helpfull? Yes (3) | No (2)  

ranjeet singh chauhan  (10 years ago)

could u please ur answer ?

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ranjeet singh chauhan  (10 years ago)

how can we find the sides of internal hexagon ?

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Nitin gupta  (10 years ago)

wudnt it be 50% ??

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saurabh prakash  (10 years ago)

ans is- 25%...

area of hexagon = 3root3 *s^2/2..

so area of original hexagon is =108root3.
area of new hexagon formed by joining mid points = 27 root 3
diff in area in %= 25%

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Amardip Gautam  (10 years ago)

inner hexagon is 37.5% of bigger hexagon if it is regular
or difference b/w the areas of 2 hexagon is 12.5% of bigger hexagon and 33.33% of inner hexagon

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avnish Rawat  (10 years ago)

25% is the wright answere
area of hexagon is (3*root3by2)*side^2
distance btwn centre and vertices be same as side 6root2

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Tarun Sharma  (8 years ago)

A regular hexagon contains 6 equilateral triangles of same area
so..side of inner trinangle is 6root2*cos 30 i.e (6.root3)/root2
so area ratio will be square of sides i.e (6*root3/root2*6*root2)^2 i.e ( root3/2)^2 i.e 3/4

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ayanava  (8 years ago)

ratio of bigger to smaler is 4:3
so (4-3)/4 = 25%

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soni kumari  (8 years ago)

correct answer will be 50%
as area of hexagon is 3pow(1%3)*side pow(2)%2

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