Latest maths Aptitude Question SOLUTION: how that, for each n greater than or equal to 3, n! can be represented as the sum of n distinct divisors of itself. (For example, 3! = 1 + 2 + 3.)

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(#M40020191) MATHS question Keep an EYE

how that, for each n greater than or equal to 3, n! can be represented as the sum of n distinct divisors of itself. (For example, 3! = 1 + 2 + 3.)

Asked In maths AISHWARYA (10 years ago)

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