Latest TCS Aptitude Question SOLUTION: In a village ,50% of the students play football, 60% of the student play basketball,40% of the student play cricket. 20% play both football and basketball ,20% play both footbal

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Algebra

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40002090) TCS Numerical Ability question Reasoning Keep an EYE

In a village ,50% of the students play football, 60% of the student play basketball,40% of the student play cricket. 20% play both football and basketball ,20% play both football and cricket,25% play both cricket and baseketball.5% of the student play all the three games and 100 students play none of the games.
1)How many students are there in the college?
2)How many students play exactly two games?
3)How many students play neither cricket nor football?
4)How many students play exactly one game?

Asked In TCS mithunprasad (12 years ago)

Solved SOURAV ROY Read Solution (13)

Is this Puzzle helpful?   (43)   (5) Submit Your Solution Algebra

Read Solution (13) :

Moumita Ghosh  (12 years ago)

we all know n(aUbUc)=n(a)+n(b)+n(c)-n(aUb)-n(bUc)-n(cUa)+n(a intersection b intersection c)=5/10+6/10+4/10-2/10-2/10-2.5/10+.5/10=9/10

the remaining 1/10 portion of people dont play anythng.
if 1/10=100,then 1=1000.

so there are total 1000 students.

5

Is this solution Helpfull? Yes (15) | No (3)  

SOURAV ROY  (12 years ago)

the student play all three games=5%
the student play only both football n bsketball=(20-5)%=15%
the student play only both football n cricket=(20-5)%=15%
the student play only both basketball n cricket=(25-5)=20%
the student play only football=(50-15-15-5)%=15%
the student play only basketball=(60-15-20-5)%=20%
the student play only cricket=(40-15-20-5)%=0%
so sdtudent play games=(0+20+15+15+15+20+5)%=90%
so student does not play games=(100-90)%=10%
as 10%=100 student den 100%=1000 student
1)there are 1000 student in the college

the student play exactly two games=(15+15+20)%=50%
50%of1000=500
2)500 student play exact two games

no of students play neither football nor cricket mens no of student play only bsketbll
so 20%of1000=200
3)200student play neither cricket nor footbll

students ply only one game=(15+20+0)%=35%
35%of1000=350
4)350students ply only one game

Is this solution Helpfull? Yes (7) | No (1)  

Ravinder Yadav  (12 years ago)

Let total no of student in college = x
n(f)=x/2
n(b)=3x/5
n(c)=2x/5
n(f U b)= x/5
n(f U c)= x/5
n(b U c)= x/4
n(f / b / c)= x/20
100 student who plays nothing
x-100=x/2+3x/5+2x/5-x/5-x/5-x/4+x/20
x=1000
(i) So 1000 students are in college
n(f)=500
n(b)=600
n(c)=400
n(f U b)= 200
n(f U c)= 200
n(b U c)= 500
n(f / b / c)= 50
now make vendiagram
(ii) total no of student who plays exactly two games = 200+200+500-50
=850
(iii) student who plays neither cricket nor football = player who plays basketball and nothibng
= 600 + 100 -500-200+50
= 50
(iV) student who plays only one game = 600+400+500-200-200-500+50= 650

Is this solution Helpfull? Yes (4) | No (1)  

Paresh  (12 years ago)

Answer :-
1) 1000
2) 500
3) 200
4) 350

more detail mail me patel.paresh894@gmail.com

Is this solution Helpfull? Yes (3) | No (1)  

deepanshu  (12 years ago)

1)1000
2)500
3)300
4)350
F=football, B= basketball, C=cricket
play all = 5
play B&C=25%, play only b&c=25-5=20%
similarly play only f&c=15%, only f&b=15%
on the basis of same logic play only f=15%, only b=20%, only c=0%
so total = 90%
who dont play nything = 100 or 10%
find the solutions of all.... :)
regards
Deepanshu Kalra

Is this solution Helpfull? Yes (2) | No (1)  

premalatha  (12 years ago)

F=football, B= basketball, C=cricket
play all = 5
play B&C=25%, play only b&c=25-5=20%
similarly play only f&c=15%, only f&b=15%
on the basis of same logic play only f=15%, only b=20%, only c=0%
so total = 90%
as given in question who dont play nothing = 100 or 10%
so the stdnts who played 90%=900

1) so the total number of students=1000

2) b&c+f&c+f&b= 20%+15%+15% =50% =500

3) no of students play neither football nor cricket mens no of student play only bsketbll
so 20%of1000=200
200 student play neither cricket nor footbll

4)students ply only one game=(15+20+0)%=35%
35%of1000=350

Is this solution Helpfull? Yes (2) | No   

AMIT KUMAR  (12 years ago)

ans is 1000....-total students
ans of 2 is 500
ans of 3 is 300
ans of 4 is 350

Is this solution Helpfull? Yes (1) | No   

ramya  (12 years ago)

total student=100+90=190
student who play two games=50
neither cricket nor football=15
only one game=35

Is this solution Helpfull? Yes | No (1)  

ankit agarwal  (12 years ago)

1) 1000 students are there in college
2) 600
3) 450
4) 400

Is this solution Helpfull? Yes | No   

akshay tr  (12 years ago)

1) n(aUbUc)= n(a)+n(b)+n(c)-n(aUb)-n(aUc)-n(bUc)+n(aIbIc)
n(aUbUc)= 50+60+40-20-25-20+5= 90
percentage of 100 who play none of the games= 10%
total number of students= 100*100/10= 1000
2) students playing exactly 2 games= n(aUb)+ n(aUc)+ n(bUc)- n(aIbIc)
=200+200+250-50=600

Is this solution Helpfull? Yes | No (1)  

Jai  (12 years ago)

Lets say there are X students in the college.
Thus number of students who play
i) all three games - 0.05X
ii) only cricket and basketball - 0.2X
iii) only football and basket ball - 0.15X
iv) only football and cricket - 0.15X
v) only cricket - 0
vi) only football - 0.15X
vii) only basketball - 0.2X
viii) neither of them - 100

0.05X + 0.15X + 0.15X + 0.2X + 0.15X + 0.2X + 100 = X
0.9X + 100 = X
X = 1000

Ans
1) 1000 students in the college
2) 500 students play exactly two games
3) 300 students play neither cricket nor football
4) 350 students play exactly one game

Is this solution Helpfull? Yes | No   

mps gupta  (12 years ago)

1. 1000 total students
2. 200 play two games
3. 300 students
4.

Is this solution Helpfull? Yes | No (1)  

Tibin Jose  (12 years ago)

1. 1000
2. 500
3. 300
4. 350

Is this solution Helpfull? Yes | No (1)  

Please Login to Read Solution.