Latest Elitmus Aptitude Question SOLUTION: What is the prob of 4 digit no formed with 1 to 5 digit to be divisible by its unit place 1 96 2 216

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(#M40020994) ELITMUS question Keep an EYE

What is the prob of 4 digit no formed with 1 to 5 digit to be divisible by its unit place
1 96
2 216

Asked In Elitmus rahul singh (10 years ago)

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Manish Pandey  (10 years ago)

4*3*2=24(when the last digit is 1 and it is divisible by 1)
4*3*2=24(when the last digit is 2 and it is divisible by 2)
4*3*2=24(when the last digit is 5 and it is divisible by 5)
3*2 =6(when last 2 digits are 24 to check it is divisible be 4)
total=78(as no digit wil be divisible by 3 keeping 3 in units place)

if digits are not repeated this should be the solution

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mayank jain  (10 years ago)

i think....
5*4*3*2=120(for checking divisibility by 1 bcos 1 is divisible by all no.s)
3*2*1*2=12(for checking divisibility by 2 ,took [2,4] as a last digit)
4*3*2*1=24(for checking divisibility by 5)
2*1*3=6(for checking divisibility by be 4,took 3 digits that is [2,3,4])
4*3*2*1=24(for checking divisibility by 3(sum of all digits is divisible by 3) so we will only take 4 digits i.e[1,2,4,5])

so total will be:-186

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