Latest TCS Aptitude Question SOLUTION: a grandfather has three grandchildren two of their young children age diff is 3,eldest child age is 3 times 2nd child's age and eldest child age is two times of sum of other two ch

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a grandfather has three grandchildren two of their young children age diff is 3,eldest child age is 3 times 2nd child's age and eldest child age is two times of sum of other two children,what is the age of eldest one.
option
a) 6
b) 18
c) 15
d) 9

Asked In TCS juhe rawat (11 years ago)

Unsolved Read Solution (8)

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Suman Saurabh  (11 years ago)

Let two young children age is x & y & elder child age =z

x-y=3

z=3x & z=2(x+y)

so x-2y =0

x=6

age of eldest child = 18

Is this solution Helpfull? Yes (8) | No   

Animesh  (11 years ago)

ans--18
logic...
let x>y>z
x=3y
y-z=3
x=2(y+z)
solving 3 eq u get the value of x... 18

Is this solution Helpfull? Yes (5) | No   

Akash Patel  (11 years ago)

z=eldest
x and y younger ( x>y)
x-y=3
z=3x
z=2(x+y)
solve the eqtn ans is z=18eldest child

Is this solution Helpfull? Yes (3) | No   

neeraj  (11 years ago)

suppose X is eldest
Y,Z r 2 younger
according to ques y-z=3
x=3y
x=2(y+z) find out value values y=6,z=3
so x=3y=3*6=18ans

Is this solution Helpfull? Yes (1) | No   

gargi mittal  (11 years ago)

let age of eldest, 2nd child nd 3rd child is x,y,z
acc to problem x=3*y and x= 2(y+z)
we knw d/f of 2nd nd 3rd child age is y-z= 3----- (1)
so now x= 2(y+z)
x=2y+2z ----- (2)
put value of x is 3y in eq (2)
3y=2y+2z so y=2z => y-2z=0 (3)
now solve eq (1) nd (3)
we get z=3 y=6 nd x=18

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swati kumari  (11 years ago)

ans-18.let the age of two young child=x and x+3 .according to question 3(x+3)=2(x+x+3) after solving we get x=3.so the eldest child is 3(3+3)=18 years

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hemendra  (9 years ago)

let first child x and second x+3,
according to question third child=3(second child),
third child=3(x+3)
again,
third child=2(x+x+3)
3(x+3)=2(2x+3)
3x+9=4x+6
x=3,
put value
third child=3(x+3)
third child=3(3+3)
third child=18 years
Hence the Eldest age is 18 years.RR

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madhu  (5 years ago)

let eldest child's age is x,next childs age is y,last childs age is z
then ,two youngest childs age diff is 3,so,y-z=3
eldest child is 3 times second child so,x=3y
and is also 2 times sum of other two childrens age so,x=2(y+z)
by solving we get x=18

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