Latest TCS Aptitude Question SOLUTION: . Inspired by Fibonacci series Sangeet decided to create his own series which is 1, 2, 3, 7, 7, 22, 15, 67, 31, _, 63? a) 202 b) 31 c) 76 d) 49

• Placement Papers
• /
• TCS
• /
• Logical Reasoning
• /
• Number Series

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40002242) TCS Logical Reasoning question Keep an EYE

. Inspired by Fibonacci series Sangeet decided to create his own series which is 1, 2, 3, 7, 7, 22, 15, 67, 31, _, 63?
a) 202 b) 31 c) 76 d) 49

Asked In TCS anandhan (12 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (24)   (4) Submit Your Solution Number Series

Read Solution (5) :

divya  (12 years ago)

ans :a(202)
consider alternative numbers 1,3,7,15,31,63
1*2+1=3,3*2+1=7,7*2+1=15,31*2+1=63
conside now remaing digits 2,7,22,67,-
2*3+1=7,7*3+1=22,22*3+1=67,67*3+1=202

Is this solution Helpfull? Yes (47) | No (3)  

Vivek Gupta  (12 years ago)

Ans: 202
its the alternative series connection
series- 1,3,7,15,31,63
as 1x2+1=3, 3x2+1=7, 7x2+1=15 and so on
likewise other series- 2,7,22,67,?
2x3+1=7, 7x3+1=22, 22x3+1=67, 67x3+1=202

Is this solution Helpfull? Yes (12) | No (1)  

sruthi reddy  (12 years ago)

Ans=202
bcos in the given series there are two other series..in the form of
1 ,2  ,3  ,7 ,7  ,22  ,15 ,67  ,31  ,_ ,63;
choose the alternate digits:1,3,7,15,31,63
these are follow the pattern like 7=n*2+1(wher n is the previous number)
15=7*2+1(where n=7)
31=15*2+1(wher n=15)
63=31*2+1(where n=31)
but we dont need this series.just for understanding i gave the above matter
anothe series in the given series in:2 ,7 ,22 ,67 ,_
we hav to find the number in the blank
this series is in the form of n*3+1
so the series consists of  the following numbers  2
7=2*3+1(where n=2)
22=7*3+1(wher n=7)
67=22*3+1(wher n=22)
for the next number we need to multiply the previous number with 3 and add a 1 to the result
finally next digit=67*3+1=202
the final series 1,2,3,7,7,22,15,67,31,202,63

Is this solution Helpfull? Yes (4) | No (3)  

Rishi Mahajan  (8 years ago)

ans : 202
there are 2 series given
1st : 1,3,7,15,31,63
1+2 = 3+2(2) = 7+4(2) = 15+8(2) = 31+16(2) = 63
2nd : 2,7,22,67,_
2+5 = 7+5(3) = 22+5(3*3) = 67+5(3*3*3) = 202

Is this solution Helpfull? Yes | No   

ARPIT SHUKLA  (7 years ago)

31
being repeated

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.