Latest TCS Aptitude Question SOLUTION: A is 20 percent more efficient then b.if the two person can complete a piece of work in 60 days.in how many days.A working alone can complete the work a) 80 b) 90 c) 100 d) 110

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A is 20 percent more efficient then b.if the two person can complete a piece of work in 60 days.in how many days.A working alone can complete the work

a) 80
b) 90
c) 100
d) 110

Asked In TCS juhe rawat (11 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

Arindam Sural  (11 years ago)

As per ques,a=(120/100)*b
=>a=(6/5)*b
therefore,b=(5/6)*a
Now,a & b complete the work in 60 days
=>(1/a)+(1/b)=60
=>(1/a)+(5/6a)=60
=>a=110

Is this solution Helpfull? Yes (36) | No (17)  

shivani semwal  (11 years ago)

a=(100+20)/100)b
a=1.2b
a=6/5b
b=5/6a
1/a+1/b=1/60
1/a+5/6a=1/60
11/6a=60
a=110

Is this solution Helpfull? Yes (11) | No (9)  

bhakti  (11 years ago)

A+B=1/60
A=(6/5)B
6x+5x=1/60
x=1/660
A's 1 day work=6*1/660=1/110
A can complete work in 110 days

Is this solution Helpfull? Yes (11) | No (2)  

Ronaksinh P Padhiyar  (11 years ago)

@arindam : why did you take 1/b=5/6a ??? because
b=5a/6 so 1/b must be 6/5a..!!!

Is this solution Helpfull? Yes (9) | No   

vishal   (9 years ago)

A's 1 day work + B 's 1 day work= 1/60
since , A=(1+20/100)B => A=6/5B
A+B=1/60
dividing both sides by A
1+B/A=1/60A
A=1/110
A=110 days

Is this solution Helpfull? Yes (2) | No   

Ishan  (11 years ago)

@arindam why dont you consider 20% efficient as taking lesser time to complete the same work?

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bindu  (11 years ago)

110 days ............as let us think b completes y amount pf work in one day then a completes y+y/5=6y/5 s combining a and b they perfoem 11y/5 amount of work per days they completed work in 60 days so total work=60(11y)/5=660y/5
now only a work speed=distance/time so time=d/s=660y/5/6y/5=110 days

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aditya wargis  (11 years ago)

as question b=(5/6)a
a+(5/6)a=(11/6)a
a:(11/6)a::60:x
x=(11/6)a*60/a=110

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Arindam Sural  (11 years ago)

@ISHAN yes man that will be also correct,but i approached the problem that way nd so continued it in my manner,taking 20% efficiency will increase da efficiency of da problem..:)

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