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(#M40023805) TCS question Maths Keep an EYE

The faces of a cube are numbered from 6 to 11 in such a way that the sum of the numbers on opposite faces is the same. What is this sum?
a. 17
b.11
c.8.5
d.6
e.51

Asked In TCS ABHIJEET RANJAN (10 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

sandy  (10 years ago)

ans : a
sum of opp faces ie, (6+11,7+10,8+9) all are equal to 17

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harsha   (10 years ago)

17, 6+11=17
7+10=17
8+9=17

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dileep  (10 years ago)

the faces to be given are (6,11) (7,10) (8,9)
therfore the sum is 17

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sandy  (10 years ago)

@DEVIKA.R:
A cube has 6 faces which are numbered as 6,7,8,9,10,11.this will have 3 opposite faces
given that the numbers are aranged in such a way that sum of numbers in 1st oppsite face is equal to sum of numbers in 2nd opposite face and also equal to sum of numbers in 3rd opposite face
therfefore the possible case is (6+11,7+10,8+9) where the sum of opposite faces is equal to 17

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Avinash Aryan  (10 years ago)

17,,

6+11,7+10 and 8+9

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Devika.R  (10 years ago)

EXPLAIN IN DETAIL

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P.VENKATA NARAYANA REDDY  (10 years ago)

17
10+7 =17
9+8 = 17
11+6 = 17

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