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(#M40023905) TCS Logical Reasoning question TCS Keep an EYE

how many arrangements will start and end with a vowel for TOGETHER?

Asked In TCS Karthika (12 years ago)

Unsolved Read Solution (7)

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Hiba   (12 years ago)

The vowels can be arranged at start and end as O..E E..O E..E so 3 ways
Consider the vowels as a single unit. You'll have
TGTHR(OEE) (6!/2!)*3 = 1080

Is this solution Helpfull? Yes (24) | No (6)  

Tejvansh  (12 years ago)

Case 1 : when first letter is "o"
the arrangements of other letters will be 6!/2!
case 2 : when first letter is "e"
the last letter will be either "o" or "e"
so the arrangements of other letters will be (2 x 6!/2!)
So the total arrangements for start and end with a vowel for TOGETHER will be
(3 x 6!/2!) = 1080

Is this solution Helpfull? Yes (13) | No (6)  

Ashutosh Dixit  (12 years ago)

No of ways to arrange vowels at first and last position is 3!/2!=3.
No of wasy of arranging remaining 6 letters=6!.
So total no of ways=3*6!.

Is this solution Helpfull? Yes (3) | No (3)  

D.Udaya sri  (12 years ago)

total 8 letters...consider vowels as one group so 6 can be arranged in 6!ways and T is repeated=6!/2! nd vowels can be arranged in 3p2/2!(3p2=3!/1!=3)...so tatal (6!/2!)*3

Is this solution Helpfull? Yes (2) | No (1)  

monica  (12 years ago)

3C1 for selecting vowels n 6!/2!*2! = 1080

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Karthika  (12 years ago)

@Tejvansh: SO yu mean "e" can be repeated,but not "t"??

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Vipul Sharma  (12 years ago)

for vowels at 1st nd last position 3!/2!
and now we are left with 6 places and 6 letters which can now be arranged as 6!
So i think answer will be 3*3*6!

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