Latest TCS Aptitude Question SOLUTION: For real number x, int(x) denotes integer part of x.int(x) is the largest integer less than or equal to x.int(1,2)=1,int(-2,4)=-3. Find the value of int(1/2)+int(1/2+100)+int(1/2+

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For real number x, int(x) denotes integer part of x.int(x) is the largest integer less than or equal to x.int(1,2)=1,int(-2,4)=-3.
Find the value of int(1/2)+int(1/2+100)+int(1/2+2/100)+....+int(1/2+99/100)

Asked In TCS kanthimathi (11 years ago)

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sandy  (11 years ago)

i too dont know how to solve but in 17th page i found the same que
ANS:
int(1/2)=0
int(1/2+100)=100
int(1/2+2/100)=0
int(1/2+3/100)=0
.....
int(1/2+50/100)=int(100/100)=1
.......
int(1/2+99/100)=int(1.49)=1
by adding all those values
we will get 150
in this the they have taken integers i.e rounded values

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aditya  (11 years ago)

sandy! how u added all the values...100+1+1=102
150? how?

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sandy  (11 years ago)

@ ADITYA
int(1/2+100)=100
AFTER THIS
FROM int(1/2+2/100) UPTO int(1/2+49/100) ARE ROUNDED AS 0
FROM int(1/2+50/100)UPTO int(1/2+99/100) ARE ROUNDED AS 1 SO 100[int(1/2+100)]+50[FROM int(1/2+50/100)UPTO int(1/2+99/100)]=150
*!!!HERE SUM LESS THAN 1(i.e,0.99,0.98.......0.1) ARE ROUNDED 0
SIMILARLY SUM FORM 1 TO 1.99 ARE ROUNDED TO 1

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sandy  (11 years ago)

@ SANDHYA
int is nothing but integer
we know that 1/2=0.5
but here SUM BETWEEN 0 AND 0.99 IS TAKEN AS 0
AND SUM BETWEEN 1 TO 1.99 IS TAKEN AS 1

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RESHAV SINGH  (11 years ago)

very good sandy...............

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Durgesh Kumar Jaiswal  (11 years ago)

answer is 150.

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sandhya  (11 years ago)

can u xpln me...further @durgesh plsssssssss

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