Latest TCS Aptitude Question SOLUTION: The total expense of a boarding house are partly fixed and partly variable with the number of boarders. The charge is Rs.70 per head when there are 25 boarders and Rs.60 when there

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The total expense of a boarding house are partly fixed and partly variable with the number of boarders. The charge is Rs.70 per head when there are 25 boarders and Rs.60 when there are 50 boarders. Find the charge per head when there are 100 boarders.

a) 65

b) 55

c) 50

d) 45

Asked In TCS hellboy (12 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

radium333  (12 years ago)

let the fixed be a and variable be k.
so, a+25k=70*25
and, a+50k=60*50
solving these we get k=50 and a=500
so for 100 boarders it will be
500+100*50=5500
per head= 5500/100 =55(ans B)

Is this solution Helpfull? Yes (13) | No   

purushotham reddy  (12 years ago)

ans:50
if the number of heads increased by 2 times then he decreases the charge by 10

Is this solution Helpfull? Yes (2) | No (7)  

harigopal  (12 years ago)

x+25y=70*25=1750 x+50y=60*50=3000
solve the both => 25y=1250
y=50 ,x=500 => 500+100*50=>5500/100=55
ans is 55

Is this solution Helpfull? Yes (2) | No   

P.K.DHARMA  (12 years ago)

if the number increases from 1st case to 2nd by 100% the cost gets low by rs 10 hence if 50*2=100,then again rate gets reduced by 10 from 2nd case as 50

Is this solution Helpfull? Yes | No (2)  

Amandeep Singh  (11 years ago)

suppose fixed amount is x and variable amount is y.
x+25y=70*25=1750.....(1)
x+50y=60*50=3000....(2)
subtract 1st from 2nd-we get---- 25y=1250
we get y=50 and x+25*50=1750
x=1750-1250=500
so for 100 boarders it will
x+100*y=500+100*50=5500
per head= 5500/100 =55

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saurabh kumar  (11 years ago)

equation for rate per head can be given as
rate per head=k/x +y,
where x= no. of boarders and y=fixed rent.
so in case of 25 boarders
70=k/25 +y
in case of 50 boarders
60=k/50 +y
solving both equations we get
k=500 and y=50


so required rate=500/100 +50=55
answer=55

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srikanth yeluri  (8 years ago)

Let fixed cost=a, variable cost=k
We can write a+25k=70*25=1750
a+50k=3000
We get k=50
then a=3000-(50*25)=500
Charge per head= (500+100*50)/100 = 55

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