Latest TCS Aptitude Question SOLUTION: In a vessel, there are 10 litres of alcohol. An operation is defined as taking out five litres of what is present in the vessel and adding 10 litres of pure water to it. What is th

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Geometry

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40024243) TCS Numerical Ability question Keep an EYE

In a vessel, there are 10 litres of alcohol. An operation is defined as taking out five litres of what is present in the vessel and adding 10 litres of pure water to it. What is the ratio of alcohol to water after two operations?
a) 1 : 5
b) 2 : 3
c) 1 : 6
d) 3 : 2

Asked In TCS Ish Mishra (10 years ago)

Unsolved Read Solution (18)

Is this Puzzle helpful?   (37)   (17) Submit Your Solution Geometry

Read Solution (18) :

rohan chawla  (10 years ago)

answer is a i.e 1:5

here vessel initially contains 10 litres of alcohol and 0 litres of water
in first operation 5 ltrs of alcohol is taken out and 10 ltrs of water is added.
so after first operation 5 ltrs of alcohol and 10 ltrs of water are there in the vessel
in the second operation 5 ltrs are again taken out
but as now alcohol and water are in the ratio of 1:2
or alcohol is one third of total quantity and water is two thirds of total quantity
so amount of alcohol taken = one third of total amount taken
=5/3 ltrs
and amount of alcohol taken = two thirds of total amount taken = 10/3 ltrs
now quantity of alcohol remaining = 5-5/3 ltrs= 10/3 ltrs
and amount of water remaining = 10-10/3 ltrs = 20/3 ltrs

after that 10 ltrs of water is added
so amount of water after that = 20/3+10 = 50/3 ltrs

so ratio of alcohol to water = (10/3)/(50/3) = 1:5

Is this solution Helpfull? Yes (111) | No (6)  

debojyoti pal  (9 years ago)

Final concentration = Initial concentration (1−replacement quantity/final volume)
Final concentration = =1×(1−10/15)=13
Final concentration = 13×(1−10/20)=16
So ratio of alcohol : water = 1 : 5

Is this solution Helpfull? Yes (6) | No (14)  

gitanjali vats  (8 years ago)

Final concentration = Initial concentration (1−replacement quantity/final volume)
Final concentration = =1×(1−10/15)=1/3
Final concentration = 13×(1−10/20)=1/6
so,after 2 operations concentration is 1/6.hence,final volume should be 6 unit.
So ratio of alcohol : water = 1 : 5 as (1+5=6)

Is this solution Helpfull? Yes (5) | No (6)  

anurag  (6 years ago)

did anyone got hall ticket..for tcs drive

Is this solution Helpfull? Yes (5) | No (1)  

deepu kumar singh  (10 years ago)

it should be 1:5 option a is correct.

Is this solution Helpfull? Yes (3) | No (7)  

sai priya.kaja  (9 years ago)

: Final concentration = Initial concentration(1−replacement quantityFinal volume)
Final concentration = 1×(1−10/15)=13
Final concentration = 13×(1−10/20)=16
So ratio of alcohol : water = 1 : 5

Is this solution Helpfull? Yes (1) | No (12)  

Harsha  (9 years ago)

priya can u xplain ur answer clearly that how 1:5 ?

Is this solution Helpfull? Yes (1) | No (3)  

Ritika Shrivastava  (9 years ago)

1:5 is the ratio

Is this solution Helpfull? Yes (1) | No (1)  

rishi  (10 years ago)

plz anyone send me TCS latest paper to this id-rishikesh0091@gmail.com
and give some tips to crack interview its urgent tcs coming for us less than 4 days........plz hurry.....

Is this solution Helpfull? Yes | No (22)  

Lokesh Kumar Fating  (10 years ago)

3 days remain 4 tcs placement
plz send any useful link or question to crack exam
my id is lokesh.fating@rediffmail.com/lokesh.fating@outlook.com

Is this solution Helpfull? Yes | No (8)  

Lokesh Kumar Fating  (10 years ago)

3 days remain 4 tcs placement
plz send any useful link or question to crack exam
my id is lokesh.fating@rediffmail.com/lokesh.fating@outlook.com

Is this solution Helpfull? Yes | No (10)  

uthra murugesan  (9 years ago)

some 1 pls clear it full confusion?

Is this solution Helpfull? Yes | No (1)  

ravi palla  (9 years ago)

i think 1:5 is correct ans

Is this solution Helpfull? Yes | No (1)  

dipali soni  (8 years ago)

not a week is left for a tcs to come..pls give some imp qs to crack the test
dipalisoni317@gmail.com

Is this solution Helpfull? Yes | No (1)  

Shubham  (8 years ago)

answer is 1:5

Is this solution Helpfull? Yes | No   

Sanket  (8 years ago)

answer is 1 because
rate of stream=1/2*(rate of downstream-rate of upstream)
0.5*2=1

Is this solution Helpfull? Yes | No (4)  

mahi  (7 years ago)

1:5

Is this solution Helpfull? Yes | No   

Raghav  (6 years ago)

only 3 days left for tcs exam. plz guide me how to study
amuraghav14@gmail.com

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.