Latest TCS Aptitude Question SOLUTION: what are the last 2 digits of (2957)^3661??

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what are the last 2 digits of (2957)^3661??

Asked In TCS Akash Tiwari (11 years ago)

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pritam kundu  (11 years ago)

57^1=57(last two digits)
57^2=49(last two digits)
57^3=93(last two digits)
57^4=01(last two digits)

57^5=57(last two digits)...here the repetation starts...so we go 4 different cases for different last 2 digits.. divide the power(3661) by 4 and take the remainder .. so, 3661%4=1..we the ans will be same as what is written in 1st case,i.e.,57^1=57... it says the final answer is 57

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Nikhil Agnihotri  (11 years ago)

ans is 57
take the last two digits from 2957 i.e 57
now count its cycle 57, 49, 93, 01, 57
thus it comes as 4
now divide 3661 by 4 , we get remainder 1 which means 57
thus it is the required answer

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