Latest TCS Aptitude Question SOLUTION: N!is having 37 zeroes at its end.How many possible values of N are possible ??

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N!is having 37 zeroes at its end.How many possible values of N are possible ??

Asked In TCS (11 years ago)

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chirag jain  (11 years ago)

To count the no of zeroes we have to count the no of 5present in them and we will calculate it as...
100! = 100/5 + 100/25 =24zeroes
and 150! = 150/5 + 150/25 + 150/125 = 37zeroes
and 155! will have 38factors thus we can say that there are 5such values from 150! to 154!

Is this solution Helpfull? Yes (43) | No (5)  

ravi kumar  (11 years ago)

150!,151!,152!,153!,154! ..... 4 possible vales of n. after 154!..155! will have 38 zeros

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anamika  (11 years ago)

ans-5
160!-164!

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Surendra Kumar  (11 years ago)

how this??























http://www.flashsandy.org/topics/fighting

Is this solution Helpfull? Yes | No (8)  

Guru Pranav  (11 years ago)

150! to 154 !

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Prerak Jain  (11 years ago)

Ans:-5
150! = 150/5 + 150/25 + 150/125 = 37zeroes
so 150 to 154, 5 values are possible.
for 155! there are 38 zeros.

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