Latest Infosys Aptitude Question SOLUTION: F(1)=1, where f(x+y)=f(x)+f(y)+8xy-2. Find f(7).

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F(1)=1, where f(x+y)=f(x)+f(y)+8xy-2. Find f(7).

Asked In Infosys asxa asxaxax (10 years ago)

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Nishant Kumar  (10 years ago)

f(2)=f(1+1)=f(1)+f(1)+8*1*1-2=1+1+8-2=8
f(3)=f(2+1)=f(2)+f(1)+8*2*1-2=8+1+16-2=23
f(4)=f(3+1)=f(3)+f(1)+8*3*1-2=23+1+24-2=46
f(7)=f(3+4)=f(3)+f(4)+8*3*4-2=23+46+96-2=163

Is this solution Helpfull? Yes (23) | No   

khushboo singh  (10 years ago)

f(1)=1
ans- 163
f(2)=f(1+1)=f(1)+f(1)+8*1*1-2=8
f(3)=f(1+2)=23
f(4)=f(1+3)=46
so f(7)=f(3+4)=163

Is this solution Helpfull? Yes (4) | No   

nithya  (10 years ago)

ans: 163
f(7)=f(1+6)=f(1)+f(6)+8(1)(6)-2 = 47+f(6)
f(6)=f(1+5)=f(1)+f(5)+8(1)(5)-2 = 39+f(5)
f(5)=f(1+4)=f(1)+f(4)+8(1)(4)-2 = 31+f(4)
f(4)=f(1+3)=f(1)+f(3)+8(1)(3)-2 = 23+f(3)
f(3)=f(1+2)=f(1)+f(2)+8(1)(2)-2 = 15+f(2)
f(1)=f(1+1)=f(1)+f(1)+8(1)(1)-2 = 8
So adding all those ans is:163

Is this solution Helpfull? Yes (1) | No   

UvRocK$  (10 years ago)

171.
following the given pattern you can get the ans.

Is this solution Helpfull? Yes | No (6)  

Selvi Raju  (10 years ago)

f(1)=1
f(1+1)=1+1+8-2=8
f(2+2)=8+8+32-2=46
f(2+1)=8+1+16-2=23
f(4+3)=46+23+128-2=195

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