Latest TCS Aptitude Question SOLUTION: Find the no. Of ways in which 210 be expressed as a product of 3 distinct factors?

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(#M40025393) TCS Numerical Ability question Keep an EYE

Find the no. Of ways in which 210 be expressed as a product of 3 distinct factors?

Asked In TCS pre (10 years ago)

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Vempa Siddhartha  (10 years ago)

210 can be written as product of prime factors ie 2X3X5X7. so the question asked to express 210 as product of 3 distinct factors means the above four prime factors combines to form 3 factors. means two factors should be combined to one factor which can be done in 4C2 ways

Is this solution Helpfull? Yes (25) | No (2)  

rohin  (10 years ago)

THE FACTORS OF 210 are 2 3 5 7...now we should choose two unmixxed term and one mixed one.so we have to select 2 out of 4...so 4C2 ways

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KOPPUROTHU PRITHVI  (10 years ago)

210=2*3*5*7
The factors can be expressed in 13ways
(105 2 1);(70 3 1);(42 5 1);(10 21 1);(14 15 1);(6 35 1);(30 7 1);(10 3 7);(6 5 7);(14 5 3);(15 7 2);(35 3 2);(21 5 2)

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RAVI GANGWAR  (10 years ago)

4c3=4
3c2=3
total no expresed=4c3*3c2=12

Is this solution Helpfull? Yes (3) | No (4)  

vinay agarwal  (10 years ago)

factor of 210 are 2,3,5,7
two factors should be combined to one factor so there are 4C2 ways
so ans is 12

Is this solution Helpfull? Yes (1) | No (7)  

Manohar  (10 years ago)

3*7*10 3 places 3 numbers can arranged in 3! ways.
so,6ways is ans.

Is this solution Helpfull? Yes (1) | No (1)  

amit   (10 years ago)

210=2*3*5*7;
so it can be expressed as in 3c2 i.e. in 6 ways
1)2*3*35
2)2*5*21
3)2*7*15
4)3*5*14
5)3*7*10
6)5*7*3

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Yati Sawhney  (10 years ago)

Aans 18
factors of 21 = 3*7*2*5
now u r to express 210 as a prod of 3 distinct factors , mind d fact that 4 factors are available .
the no of ways in which a pair cn be formed is C(4,2) = 6
Now each of this pair can be arranged with the remaing 2 no in 3 ways
Hence the total no of ways = 18

Is this solution Helpfull? Yes | No (5)  

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