Latest TCS Aptitude Question SOLUTION: two people one young and one old live together,and work in the same office it takes 20min and 30min respectively to walk from home to office when the young man catchup with the old

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(#M40025807) TCS Numerical Ability question Keep an EYE

two people one young and one old live together,and work in the same office it takes 20min and 30min respectively to walk from home to office when the young man catchup with the old man if the oldman starts at 10am and young at 10.05am?

Asked In TCS krishna (11 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

kaustubh ingale  (11 years ago)

10.15 am is the answer.

Is this solution Helpfull? Yes (8) | No (2)  

D G  (11 years ago)

at 10.15 am...

Is this solution Helpfull? Yes (4) | No (2)  

aditya jain  (10 years ago)

let x hours after he will meet.
so ,
distance travel by young boy in (5+x) min =distance travel by old man in x min.
let d be a total distance.
so
(5+x)d/20=x*d/30
x=15min
10:00 am +15 min
=10:1 am

Is this solution Helpfull? Yes (3) | No   

pankaj kandpal  (11 years ago)

let the distance be x..
now dis covered is same , let their speeds are y and o..
then y*20/60=o*30/60;
i.e. o=2y/3;
so relative speed is y-2y/3=y/3
with this relative velocity young has to cover (2y/3)*(5/60) m
i.e. y/180 m so it will take time =(y/180)/(y/3)=1/60 hr=1 min.
so he would catch at 10:06 am...

Is this solution Helpfull? Yes (2) | No (4)  

pankaj kandpal  (11 years ago)

o yes 10:15 mistakenly done y/180 instead of y/18....

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Utkarsha Singh  (11 years ago)

10;15am answer

Is this solution Helpfull? Yes (1) | No   

Akhil Sharmaq  (11 years ago)

10:15am is the answer

Is this solution Helpfull? Yes (1) | No   

aditya jain  (10 years ago)

above will v 10:15 am

Is this solution Helpfull? Yes (1) | No   

anish kumar  (10 years ago)

if young man starts 10 minute late ,he catches after 20 mintutes
10 min.........20 min
5 min............(20/10)*5=10 min late
ans...10:15

Is this solution Helpfull? Yes (1) | No   

suraj shaw  (10 years ago)

let x hours after he will meet.
so ,
distance travel by young boy in (5+x) min =distance travel by old man in x min.
let d be a total distance.
so
(5+x)d/20=x*d/30
x=15min
10:00 am +15 min
=10:15am

Is this solution Helpfull? Yes | No   

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