Latest SSC Aptitude Question SOLUTION: A can do a piece of work in 24 days, B in 52 days and C in 64 days. All being to do it together, but A leaves after 6 days and B leaves 6 days before the completion of the work. Ho

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(#M40025843) SSC Numerical Ability question SSC-CGL quant Keep an EYE

A can do a piece of work in 24 days, B in
52 days and C in 64 days. All being to do
it together, but A leaves after 6 days and
B leaves 6 days before the completion of
the work. How many days did the work
last?

Asked In SSC Rats (10 years ago)

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SANJEEV KUMAR PANDIT  (7 years ago)

*I think you have mistakenly written 32 as 52 for B(as per SSC Paper)* but still solving with your given data

A takes 24 days
B takes 52 days
C takes 64 days
So, Total work = LCM of (A,B,C)
LCM (24,52,64)=2496 units
So, efficiency of A= 2496/24 = 104 units
efficiency of B= 2496/52 =48 units
efficiency of C= 2496/64= 39 units
efficiency of A+B+C = 191 units
So they worked for 6 days before A leaves
i.e. Work done =191*6 =1146 units
Remaining Work = 2496-1146 =1350 units
Now , B left C alone for 6 days. So, C alone did 6 days work
i.e. Work Done=39*6=234 units
Remaining Work = 1350-234= 1116 units ,which was done by both B and C
So, Days taken by B+C=1116/(efficiency of B and C)=1116/87=12.82

Total Days taken= 6+6+12.82=24.82= 25 (approx) Ans.

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