Latest TCS Aptitude Question SOLUTION: A number when divided by D give remainder 23 and when by 12D give 104.What will be remainder when divide by 6D? a. 23 b. 47 c. 52 d. 104

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A number when divided by D give remainder 23 and when by 12D give 104.What will be remainder when divide by 6D?

a. 23
b. 47
c. 52
d. 104

Asked In TCS Rana (10 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

rajesh ray  (10 years ago)

N = ad + 23 when N divided by D quotient is a
N = 12bD + 104 when N divided by 12D quotient is b
let b = 1
N = 12D + 104
aD + 23 = 12D + 104
D(a – 12) = 81
D = 81/(a – 12)
least value of a = 15 so (a – 12) divides 81 exactly
so D = 27
N = 15 × 27 + 23 = 428
6D = 27 × 6 = 162
428/162 = Remainder is 104

Is this solution Helpfull? Yes (42) | No (8)  

Saurabh Bhan  (10 years ago)

it's a trick, when n/12D gives 104. We can write n/6D as 2n/12D i.e (n+n)/12D. So it would give 104+104=208 as remainder, but acc. to remainder theorem we need to multiply d answer by the factor dat we hav divided with and that was 2. So the answer would b 104, this trick is working in each n every case.

Is this solution Helpfull? Yes (19) | No (2)  

Ann Mary Jolly  (10 years ago)

Let N be the no.,so according to wat's given, D>23 =>6D>138 =>12D>276.
Also N = 12D*m + 104 = 6D*2m + 104,here,when N is divided by 6D, the remainder is either 104 or a no. lesser which means 104 could be again divided by 6D.
But we know that 6D > 138 ie. 6D > 104.
Therefore 104 cannot be further divided by 6D.Therefore the remainder is 104.

Is this solution Helpfull? Yes (6) | No (2)  

ANNA POL  (10 years ago)

Ans 104. D>23 i.e. 24,25.... when we divide 104 by 24*6 reminder should be 104

Is this solution Helpfull? Yes (1) | No (2)  

Guru Pranav  (10 years ago)

when divide by 6D give 104

Is this solution Helpfull? Yes (1) | No (1)  

ashviny  (9 years ago)

i think answer will be 23

Is this solution Helpfull? Yes (1) | No (1)  

ayesha  (4 years ago)

N = ad + 23 when N divided by D quotient is a
N = 12bD + 104 when N divided by 12D quotient is b
let b = 1
N = 12D + 104
aD + 23 = 12D + 104
D(a – 12) = 81
D = 81/(a – 12)
least value of a = 15 so (a – 12) divides 81 exactly
so D = 27
N = 15 × 27 + 23 = 428
6D = 27 × 6 = 162
428/162 = Remainder is 104

Is this solution Helpfull? Yes (1) | No   

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