Latest TCS Aptitude Question SOLUTION: From the top of a building 60 metres high the angles of depression of the top and bottom of a tower are 30° and 60° respectively. The height of the tower is, option (A) 40m

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(#M40026190) TCS Numerical Ability question Keep an EYE

From the top of a building 60 metres high the angles of depression of the top and bottom of a tower are 30° and 60° respectively. The height of the tower is,
option
(A) 40m
(B) 30m
(C) 20m
(D) 50m
(E) 23m

Asked In TCS ASD (10 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

amit kumar burnwal  (10 years ago)

as given,
From the top of a building 60 metres high the angles of depression of the top and bottom of a tower are 30° and
60° respectively,
hence,
applying tan 60 = p/b =60/base i.e, base = 60/tan 60,
again,
tan 30 = p/b = p/(60/tan 60)
hence, p=20 meters
so,The height of the tower = (60-20)meters
= 40 meters

Is this solution Helpfull? Yes (20) | No (2)  

ravendra tiwaree  (10 years ago)

answer is 40 only..

Is this solution Helpfull? Yes (2) | No (1)  

Suyash Kunawat   (10 years ago)

[a] 40m
60/b=tan(60)
b=20(sqrt3)
now p1/20(sqrt3)=tan(30)
so p1=20
hieght of tower is 60 -20= 40m

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prabin jain  (8 years ago)

40 is ans......

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