Latest TCS Aptitude Question SOLUTION: remainder of 6^17+17^6 when divided by 7

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(#M40026194) TCS Numerical Ability question remainder Keep an EYE

remainder of 6^17+17^6 when divided by 7

Asked In TCS vijeta dass (10 years ago)

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Read Solution (3) :

Vinay Jain  (10 years ago)

Split the above expression in two parts :-

(6^17)/7 + (17^6)/7

Now 6 when divided by 7 gives remainder 6 or -1, so we can write
(6^17)/7 = (-1)^17 = -1

Also
17 when divided by 7 gives remainder 3
So we can write it as (3^6)/7
Using cycle of 3 we can find the remainder of above term as:-

3 / 7 remainder= 3
3^2 / 7 remainder= 2
3^3 / 7 remainder= 6
3^4 / 7 remainder= 4
3^5 / 7 remainder= 5
3^6 / 7 remainder= 1

So final answer will be (-1 + 1) = 0 ans

Is this solution Helpfull? Yes (27) | No (2)  

Manish Singh  (10 years ago)

given (6^17)/7+(17^6)/7
reminder= ??
so first divide 6 by 7 we get either 6 or -1
and when 17 is divided ,rem=3
after continuing it we have -1+1=0 ans

Is this solution Helpfull? Yes (3) | No (7)  

Guru Pranav  (10 years ago)

6^17)/7 = (-1)^17 = -1
3^6 / 7 remainder= 1
(-1 + 1) = 0 ans

Is this solution Helpfull? Yes (1) | No   

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