Latest TCS Aptitude Question SOLUTION: What is the distance between the z-intercept from the x-intercept in the equation ax+by+cz+d=0. (I do not remember the values of a,b,c,d)

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What is the distance between the z-intercept from the x-intercept in the equation ax+by+cz+d=0. (I do not remember the values of a,b,c,d)

Asked In TCS Bhavesh Dabgar (13 years ago)

Solved Prasenjit Boral Read Solution (5)

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sanjeet kumar pal  (10 years ago)

ax+by+cz+d=0
At the z-intercept, 'x' and 'y' are both zero.
cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).
At the x-intercept, 'y' and 'z' are zero.
ax + d = 0 --> x = -d/a --> The x-intercept is the point (-d/a, 0, 0).
The distance between the points (0, 0, -d/c) and (-d/a, 0, 0) is

{ Formula: sqrt((x-x1)^2 + (y-y1)^2+(z-z1)^2) }

=> sqrt((0-(-d/a))^2 + (0-0)^2+((-d/c)-0)^2)
=> sqrt((d/a)^2+(d/c))^2

submit the values...

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Prasenjit Boral  (13 years ago)

z intrcpt = -d/c x intrcpt= -d/a distance= sqrt(d2/(c2+a2))

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ruchin sharma  (13 years ago)

ans sqrot((da)^2+(db)^2)

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kirubakaran  (11 years ago)

ans: sqrt ((d/a) 2+ (d/c) 2)

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swati saxena  (9 years ago)

z intercept , doing x=y=0 , z= -d/c , point P1(0,0,-d/c)
x intercept , y=z=0 x= -d/a , point P2(-d/a,0,0,)

Distance P1P2 = I P1-P2I = I (d/a),0, (d/c) I = sqrt ((d/a)^2+ (d/c)^2)

P1P2 = d sqrt ( (1/a)^2 +(1/c)^2)

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