Latest TCS Aptitude Question SOLUTION: A cow and horse are bought for Rs.2,00,000. The cow is sold at a profit of 20% and the horse is sold a t a loss of 10%. The overall gain is Rs.4000, the Cost price of cow? a) 1300

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(#M40026400) TCS Numerical Ability question Keep an EYE

A cow and horse are bought for Rs.2,00,000. The cow is sold at a profit of 20% and the horse is sold a t a loss of 10%. The overall gain is Rs.4000, the Cost price of cow?
a) 130000
b) 80000
c) 70000
d) 120000

Asked In TCS naveen (10 years ago)

Solved Akash Deshwal Read Solution (22)

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Read Solution (22) :

Akash Deshwal  (10 years ago)

Ans b) 80000
x+y = 2,00,000
1.2x+0.9y = 2,04,000

solving these two equation we get x=80,000

Is this solution Helpfull? Yes (92) | No (4)  

kavitha  (10 years ago)

cow=x,horse=y
x+y=200000
120*x/100+90*y/100=204000
on solving tis we get
x=80000 y=120000

Is this solution Helpfull? Yes (28) | No (1)  

mounika  (10 years ago)

x+y=200000 ------> eqn1 [assume x=cow and y=horse]
20%x profit-10%y loss=4000
(20/100)*x-(10/100)*y=4000
2x-y=40000 --------> eqn2
by solving eqn1 and eqn2
we get x=80,000 and y=1,20,000
ans is 80,000

Is this solution Helpfull? Yes (15) | No (1)  

Gaurav Nagdev  (10 years ago)

B) 80000
20% profit on 80000= 16000/-
10% loss on 120000=12000/-
Hence total profit made=16000-12000=4000/-
Hence cost of cow = 80000/- and cost of horse=120000/-

Is this solution Helpfull? Yes (6) | No   

prafull mittal  (10 years ago)

C+H=200000
therefore
c= 20%C = (120/100)C
H= -10%H= (90/100)H
so,
C+H=2,00,000+40,000=1.2C+09H ... cost price = 80,000

Is this solution Helpfull? Yes (6) | No (1)  

pesaru karthik reddy  (10 years ago)

c+h=2,00,000
1.2 c + 0.9 h=2,04,000.
c=80,000.

Is this solution Helpfull? Yes (5) | No (1)  

Nitin Kumar  (10 years ago)

120*x/100+90*y/100=204000
plz explain this calculation

Is this solution Helpfull? Yes (4) | No (2)  

tejomay saha  (10 years ago)

it can be solved quickly by hit and trial method if cow prizefrom option=130000,80000,700000,120000 so the corrsponding horse cost respectively 70000,120000,130000,80000 .now applying the cnodition we get cow cost=80000

Is this solution Helpfull? Yes (2) | No (3)  

AVINASH KUMAR SINHA  (10 years ago)

cp of cow will be 80000

Is this solution Helpfull? Yes (1) | No (1)  

shashi goswami  (10 years ago)

c+h=20000
and c/5-h/10=4000
by solving these two we get c=80000
ans is b)80000

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pratik jitendra malviya  (10 years ago)

ans. 80,000

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Guru Pranav  (10 years ago)

x+y = 2,00,000
1.2x+0.9y = 2,04,000

so x= 80000.

Is this solution Helpfull? Yes (1) | No (1)  

Souvik Saha  (6 years ago)

Overall profit =
4000
200000
×
100
=
2
%
4000200000×100=2%
By applying alligation rule, we get


So cost price of the cow = 2/5 x 200000 = 80,000

Is this solution Helpfull? Yes (1) | No   

aditi bose  (10 years ago)

let c.p of cow be x, c.p of horse is 200000-x
s.p= {(p+100)*c.p}/100 and s.p={(100-L)*c.p)}/100
using the formula s.p for cow is 120x/100
nd for horse is {(200000-x)*90}/100
find total sp nd subtract it from total cp (given) which is the gain (4000 given) ... you will find x which is the cp of the cow. 80000

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saidulushaik  (9 years ago)

let cow c.p=x
horse=200000-x
120/100)*x+(90/100)*(200000-x)=4000

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sandeep kumar  (9 years ago)

ANS =B
C+H=2,00,000 RS
1.2X+0.9Y=2,04,000 RS
X=80,000 RS

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gowthami majji  (9 years ago)

cost of the cow is 80000
cost of the horse is 120000
i.e
c+h=200000
profit of the cow 20% =120000
loss of the horse 10%=90000
overall gain amount is 4000
120*c/100+90*h/100=204000

Is this solution Helpfull? Yes | No (2)  

Yadav Chevula  (8 years ago)

ans:80000
let horse cost is : h
then cost of cow=200000-h
20% profit on cow +10% loss on horse and overall profit=204000
so
(90*h)/100 + (200000-h)*(120)/100 = 204000
after solving
cost of horse = 120000
cost of cow = 80000

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Ankita Dasgupta  (8 years ago)

THE EQUATION CAN BE WRITTEN AS
(20/100)*X-(10/100(200000-X))=4000 (LET THE PRICE OF THE COW BE X AND HORSE BE 200000-X)
X=80000

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Arunima   (8 years ago)

.2x-20000+.1x=4000
x=80000

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Yuvaraj   (7 years ago)

b) 80000
c+h=2,00,000
1.2c+.9h=2,04,000
c=80000

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Chandramohan  (3 years ago)

The answer is 80000

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