Latest Wipro Aptitude Question SOLUTION: When not moving on the sidewalk, Maya can walk the length of the sidewalk in 7 minutes. If she stands on the sidewalk as it moves, she can travel the length in 4 minutes. If Maya w

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When not moving on the sidewalk, Maya can walk the length of the sidewalk in 7 minutes. If she stands on the sidewalk as it moves, she can travel the length in 4 minutes. If Maya walks on the sidewalk as it moves, how many minutes will it take her to travel the same distance? Assume she always walks at the same speed, and express your answer as a decimal to the nearest tenth.
(a) 3.6 (b) 2.5 (c) 3.8 (d) 2.8

Asked In Wipro shiny (11 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

Tushar Shukla  (11 years ago)

assume distance of sidewalk "x"
speed1 (moving on sidewalk)
speed2 (moving off sidewalk)
since both the movements are in same direction, we can do speed1 + speed 2
speed1 = x/4
speed2 = x/7
speed1 + speed2 = 11x/28 = 0.39286x
now new time while moving on sidewalk = x/0.39286x = 2.54544
hence, the answer is 2.5

Is this solution Helpfull? Yes (16) | No (3)  

roshan zatale  (11 years ago)

walk in 7 min
as it move she can cover in 4 min as she require less time to move so we considor the respective ration.here only we have to match 4 min of moving bcs here both speed are added
1 min speed of walk respect to move 4/7=0.57
now as she walk on side walk as moves
we have to considor both speed
now we get both speed now simpli by adding get answer
now we know that as she covers a distance in 2 min+ distance cover by walk in 2 min
i,e 2+1.14=3.14
now for remaining it require 0.5 min
so by walking she cover 0.27 and moving 0.5
so total is 4 and time is 2.5
i think ans 2.5

Is this solution Helpfull? Yes (11) | No (3)  

Diwakar Reddy  (11 years ago)

V1 be the velocity of maya = L/t1
V2 be the velocity of sidewalk = L/t2
as the travelling lenght is same V1t1=V2t2
V1=V2*t2/t1
V3(velocity when maya walks on the sidewalk) = V2+V1 = V2*(1+(t2/t1))
V3t3=V2t2
t3=t2/(1+(t2/t1))
= 4/(1+(4/7))
= 2.54

Is this solution Helpfull? Yes (7) | No   

Satyendra Singh  (11 years ago)

b because
7 minutes when sidewalk and maya not moving covers distance = L
1 minute --------------------------------------------------= L/7
4 minutes when sidewalk moving and maya not moving covers distance = L
1 minute --------------------------------------------------= L/4
so total moving when sidewalk is moving and maya also = L/7 + L/4 = L/(28/11)
its mean that in 1 minute she covers L/2.5 distance so in 2.5 minute she will cover L distance.

Is this solution Helpfull? Yes (3) | No   

ramyajyothi  (11 years ago)

let Maria live x miles from the mountains
Let her rate to mountains be y
t=d/r
x/y = 9
x=9y
Return trip 4 hours
rate = y+40
x/(y+40) =4

substitute x
9y/(y+40)=4
9y=4y+160
9y-4y=160
5y=160
y= 160/5
y=32
x=9y
x=9*32= 288 miles
distance to the mountain = 288 miles

Is this solution Helpfull? Yes | No (2)  

PAVITHRRESH S V  (10 years ago)

distance required = 1/7 + 1/4
= (4+7)/28
= 11/28
= 1/2.5454 = 2.5454 min

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