Latest TCS Aptitude Question SOLUTION: 19. What is the remainder if the no. 123456789101112....143144 is divided by 35?

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19. What is the remainder if the no. 123456789101112....143144 is divided by 35?

Asked In TCS pre (10 years ago)

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Paramita Goswami  (10 years ago)

4, because by multiplying 5 with 1-9 numbers we can only get 0 and 5 in the very first position,so in this question 4 is placed in the very first position so by dividing it by 35 can give 0,so 4 becomes the remainder.

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Shivam Sangal  (10 years ago)

n=144
sum of natural no=(n(n+1))/2
sum=10440
when divided by 35 it gives remainder=10

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sakunthala  (10 years ago)

divide 35 means if the number unit digit is 0, or 5 so the remainder is 4

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aditya pratap singh  (10 years ago)

n(n+1)/2
n=44
so 44(45)/2=990
so remainder=990%35=10
answer:-10

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ira upadhyay  (10 years ago)

remainder 2?

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prabhat kumar  (10 years ago)

this no after divided by 35 we get reamainder is 24.

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Kalpesh Prajapati  (8 years ago)

Let N = 1234567891011121314151617181920......424344
Remainder when N is divided by 5 is 4. So N = 5K + 4 .....(1)
Remainder when N is divided by 9 is Sum of the digits of N divided by 9. We know that 1+2+3+...44 = 990 Which
gives digit sum as 9. So remainder when N is divided by 9 is 0.
So N = 9L .....(2)
Equation (1) and (2) we 9L = 5K + 4
For K = 1 this equation gets satisfied. So least possible number satisfies the condition is 9
So The general format of N = w(LCM of (9, 5)) + Least number satisfies the condition.
So N = w.45 + 9
When N is divided by 45, we get 9 as remainder.

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