Latest TCS Aptitude Question SOLUTION: Find the equation of the straight line which passes through the point (3, 4) and has intercepts on the axes such that their sum is 14 option a. 4x+3y =24 b. x+y=7 c. 3x+7y =43

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Find the equation of the straight line which passes through the point (3, 4) and has intercepts on the axes such that their sum is 14

option
a. 4x+3y =24
b. x+y=7
c. 3x+7y =43
d. Both(1)and(2)

Asked In TCS (11 years ago)

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j.s.b.subramanyam  (11 years ago)

Given that st line passes through (3,4) and so checking the opts both a,b satisfy...now calculate intercept for both a,b.. in equ a==> for x intercept put y=0 ====>4x=24 and x=6..similarly y interecpt ..put x=0===>3y=24 and y=8... so their sum is 6+8=14..... and now in equ b ... x-intercept=7,y-intercept=7..sum of intercepts is 14... so answers in opt d.. both

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Suchitra  (11 years ago)

check from options..given that sum of intercepts should be 14
so consider 4x+3y=24
4x=24,x=6 so x-intercept=6 and
to find y-intercept consider x=0 we get
3y=24,y=8 so y-intercept=8
now x-intercept+intercept=8+6=14...so 4x+3y=24 is the answer

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Santanu Ganguly  (11 years ago)

d)both 1 & 2......
x/a+y/b=1 then put b=14-a
then x/a+y/14-a=1
hence a=7 or 6
so, b= 7 or 8

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Santanu Ganguly  (11 years ago)

x/a+y/b=1
x/a+y/(14-a)=1
then a=7 or 6
so b=7 or 8
so x+y=7 or 4x+3y=24

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ABHAY KUMAR  (11 years ago)

for both the lines of option a and b, the above case satisfies. Now for clarification solve both the equation of option a and b the common point that will come is (3,4). Thus both the lines intersect at that point.

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kvr sudheer  (11 years ago)

a.4x+3y=24
=>substitute (3,4) it satisfies and then the x intercept and y intercept are 6 and 8 respectively so the equation satisfy the given conditions

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