Latest TCS Aptitude Question SOLUTION: a man cannot remember the number larger than 15. However he remember any number upto 100 by remembering the three numbers obtained as remainders when the numbers is divided by 3,7

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(#M40029948) TCS Logical Reasoning question Keep an EYE

a man cannot remember the number larger than 15. However he remember any number upto 100 by remembering the three numbers obtained as remainders when the numbers is divided by 3,7 and 11 respectively. he remembers that he had (2,4,8) rupees in his purse. and he paid (2,5,4)rupees to the servant. How much money is left in the purse?

Asked In TCS pre (10 years ago)

Unsolved Read Solution (6)

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sangani devi  (10 years ago)

the number that satisfies the all remainders of 2,4,8 by numbers 3,7,11 respectively is 74.
and the the number that satisfies the all remainders of 2,5,4 by numbers 3,7,11 is 26.
hence the remaining money is=74-26=48
ans is 48

Is this solution Helpfull? Yes (36) | No (1)  

prasanna kumar kotteti  (10 years ago)

take the number which gives remainder as 8 when divide with 11 below 100.they are
19 30 41 52 63 74 85 96 and in that take numbers which gives 2 as remainder when divide with 3 are 41,74 then in this which gives remainder 4 when divide with 7 is 74 like wise we can do for paid amount also.

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juhe rawat  (10 years ago)

rs 81 is left in the purse....

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pre  (10 years ago)

sangani:..how u find 74 and 26.plss explain

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Shatadru Roy Chowdhury  (10 years ago)

SANGANI DEVI how did u get 74 and 26, pls explain.

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dharmendra  (10 years ago)

the total amount must be one of... 11x+8(19,30,41,52,63,74,85,96)... thus 74 is total amount.. and paid amount must be 11x+4 (15,26,37,48,59,70,81,92)... 26 satisfies all conditions thus money left (76-26=48)

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