Latest TCS Aptitude Question SOLUTION: Three cars A, B and C are participating in a race.A is twice as likely as B to win and B is thrice as likely as C to win. What is the probability that B will win, if only one of t

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Three cars A, B and C are participating in a race.A is twice as likely as B to win and B is thrice as likely as C to win. What is the probability that B will win, if only one of them can win the race?

Asked In TCS Harsha (10 years ago)

Solved Anchuri Sandeep Reddy Read Solution (8)

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Read Solution (8) :

animesh jain  (10 years ago)

p(A)=2*p(B)
P(B)=3*p(c)
P(A) +P(B)+P(C) =1
2 * P(B) + P(B)+P(B)/3 =1
10*p(B) /3=1
P(B)=3/10

Is this solution Helpfull? Yes (58) | No   

Anchuri Sandeep Reddy  (10 years ago)

Let the probability of A to win is 'x'. Now B to win is A/2 i.e x/2.
Now C to win is B/3 i.e x/6.
So inorder to B to win the probality is (x/2)/(x+x/2+x/6)=3/10.

Is this solution Helpfull? Yes (28) | No (4)  

saranya sankar  (10 years ago)

let B's chance is x
then A's chance is 2x
C's chance is (1/3)x.....(as B is thrice of the c)
A:B:C=2x:x:(1/3)x
=6:3:1
so the probability of B is =3/10

Is this solution Helpfull? Yes (4) | No   

Shubhankar Datta  (9 years ago)

let B's chance is x
then A's chance is 2x
C's chance is (1/3)x.
A:B:C=2x:x:(1/3)x
=6:3:1
winning probablity
so p(A)=6/10
p(B)=3/10
p(C)=1/10
then the probablity that only B can win=(winning probablity of B)*(losing probablity of A)*(losing probablity of C)
=3/10*(1-6/10)*(1-1/10)
=.108

Is this solution Helpfull? Yes (2) | No   

SATYA NAYAK  (10 years ago)

ans is 27/250

Is this solution Helpfull? Yes | No (7)  

Lavanya  (10 years ago)

p(b)=3/10
but only probability of b is 27/250

Is this solution Helpfull? Yes | No (7)  

Ashwin Kumar  (2 years ago)

Answer is 3/10

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Rohit kushwaha  (2 years ago)

A:B=2:1
B:C=3:1
A;B:C=6:3:1
B=3/10

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