Latest TCS Aptitude Question SOLUTION: Numbers from 1 to 10^2012 are given, there are 'm' no of 1's and 'n' no of 2's. Then what is (m-n).

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Numbers from 1 to 10^2012 are given, there are 'm' no of 1's and 'n' no of 2's.
Then what is (m-n).

Asked In TCS Anchuri Sandeep Reddy (10 years ago)

Solved sai sirish Read Solution (6)

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Read Solution (6) :

sai sirish  (10 years ago)

ans=1
let consider from 1 to 10^2(no. of 1s and 2s are same in between 1 and 99)as no.of 1s 1 to 9=1,10-19=11,20-29=1,30-39=1,40-49=1,50-59=1,50-69=1 ....90-99=1
2s 1 to 9=1,10-19=1,20-29=11,30-39=1.............................90-99=1
the no. of 1s and 2s between 1 and 10^2 -1 are same
similarly no. of 1s and 2s btwn 1 and 100^2012-1 will be same 1 more 1 will be in 10^2012

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aravind  (10 years ago)

let us consider 1-100 here no of 1's m =21 and no.of 2's n = 20 there by m-n=1 similary from 1 to (10^2012-1) no.of 1's=no.of 2's but in last term 10^2012 a one is added there by the ans is 1.

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swethakottakota  (10 years ago)

1 is the answer

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NILAPU VARAPRASAD REDDY  (10 years ago)

answer is 1
no. of 1's and 2's are same upto 1 to {(10^2012)-1}

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THUDUM VENKATESH  (10 years ago)

1 is my answer

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Ashita saxena  (9 years ago)

it can't be tcs question .

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