Latest Others Aptitude Question SOLUTION: Q. A group of 630 children arranged in group.each row contain 3 fewer children than the row front of it.how many rows of numbers are possible?

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Q. A group of 630 children arranged in group.each row contain 3 fewer children than the row front of it.how many rows of numbers are possible?

Asked In Others chithra nair (11 years ago)

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Smarty  (11 years ago)

Answer: 21
Explanation:Each row contains 3 greater than the front row..
So, the order follows...
1st row 3, 2nd row 6 and so on.... which indicates an Arithemetic Progression(A.P)
we don't know no.of terms in the series... but the sum is 630 i.e., the total no.of children.
n(2a+(n-1)d)/2 = 630
a=3, d=3
substituting and solving we get n=21,the no.of rows required....

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Dr.Dipin Singh  (11 years ago)

number of rows will be 20.
check

n(2a+(n-1)d)/2 = 20(6+19*3)/2= 10*63=630

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Vijay Singh Adhikari  (11 years ago)

Answer is 20

3(1+2+3+.....N)=630
3[N(N+1)/2]=630
N(N+1)/2=210
N(N+1)=420
solving we get N=20,-21
so No. of possible rows are 20.

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chithra nair  (11 years ago)

i dunno d ans.

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