Latest Miscellaneous Company Exam Aptitude Question SOLUTION: Q. 25% students of a class failed in Chemistry and 40% failed in Physics where 10% did not pass in any of the two subjects. If 30 students passed in only Physics, how many of them

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(#M40031116) MISCELLANEOUS COMPAN Numerical Ability question Keep an EYE

Q. 25% students of a class failed in Chemistry and 40% failed in Physics where 10% did not pass in any of the two subjects. If 30 students passed in only Physics, how many of them passed in both the subjects.

Asked In Miscellaneous Company Exam susi (10 years ago)

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susi  (10 years ago)

n(C)=75% , n(P)=60% , n(PUC)= 90% => n(PnC)= 75% + 60% - 90% = 45%. given n(P) - n(PnC)= 30 , 60% - 45% = 30 => 15% = 30 => 1% = 2 . n(PnC) = 45% = 90

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palu  (10 years ago)

n(C fail)=25% => n(c pass)=75,
n(p fail)=40% => n(p pass)=60,
n(PUC fail)= 10% =>n(PUC pass)= 90%,
n(PnC pass)= n(p pass)+n(c pass)-n(PUC pass)=75% + 60% - 90% = 45%.
we have n(P pass) - n(PnC pass)= 30,
=> 60% - 45% = 30
=> 15% = 30
=>1%=2,
n(PnC pass) = 45%
=>2*45=90. ans=90.

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SAHELI BANERJEE  (10 years ago)

25x/100+40x/100-10x/100=11x/20 , x-11x/20=9x/20, 25%of x - 10% of x=no. of people passed in physics=30(given), now x=200, from that 9x/20=90 ans.

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dineshdevaki  (10 years ago)

30 students passed only in physics means failed in chemistry
so total chemistry failures - both failures gives only chemistry failures
(25%-10%)x = 30 => 15%x=30 => x=200
toatal pass = 100%-25%-40% =35%
35%= 70 students passed in both

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vimal  (10 years ago)

bhai koi easy way me batao please..

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edwin jebakumar  (10 years ago)

n(C fail)=25%, n(C pass)=75%
n(P fail)=40%, n(P pass)=60%
n(both fail)=10%, n(any 1 pass)=90%
n(passd only physics)=n(any 1 pass)-n(P pass)
30 =90%-60%
30=15x/100
x=200
n(all pass)=n(P pass)+ n(C pass)-n(any 1 pass)
=60%+75%-90%
=45%
hence, (45*200)/100= 90

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