Latest Infosys Aptitude Question SOLUTION: Q. Find the 3 digit no. whose last digit is the squareroot of the first digit and second digit is the sum of the other two digits

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Q. Find the 3 digit no. whose last digit is the squareroot of the first digit and second digit is the sum of the other two digits

Asked In Infosys RagunathKC (10 years ago)

Unsolved Read Solution (16)

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Read Solution (16) :

RAKESH  (10 years ago)

let xyz be the digits of no.,then
z=sqrt(x)
y=x+z=x+sqrt(x)
so no. is =100x+10y+z
=100x+10(x+sqrt(x))+sqrt(x)
=110x+11*sqrt(x)
if x=1, no. is =121
if x=4, no. is =462
if x=9, no. is =990+33=1023(not 3 digit)
two no's 121 & 462

Is this solution Helpfull? Yes (41) | No   

Mani  (10 years ago)

3 digit number
so __ __ __
in that gap we get
(x) (x+sqrt(x)) sqrt(x)
digits are 0,1,2,3,4,5,6,7,8,9
sqrt applicable for 1,4,9
first take 1 then number is 121
second take 4 then number is 462
third take 9 then number is 9123 which is not 3 digit numb
so ans is 121 and 462

Is this solution Helpfull? Yes (11) | No (2)  

mahima srivastava  (10 years ago)

let first digit be a then the number will be a (a+root(a)) root(a)
if a=4
then root(a)= 2
a+root(a)=6
for any other value of a value of a+root(a) will not be a single digit and the number has to be a 3 digit number
so, the number will be 462

Is this solution Helpfull? Yes (5) | No (1)  

Dhanashri  (10 years ago)

single digit that must be square of other digit ,only 4 and 9 is on focus.
hence as per given terms,that nuber looks somewhat
4_2 or 9_3;
but middle is sum of other two number hence,
9+3=12 is not possible,
the digit is
462

Is this solution Helpfull? Yes (3) | No   

varshika  (10 years ago)

lets 3 digit no is xyz
z=squareroot(x)
y=x+z
lets consider x=1
z=squareroot(1)=1
y=1+1
so ans is 121

Is this solution Helpfull? Yes (1) | No   

diya  (10 years ago)

digits are : x^2 x^2+x x
possible no.: 1 2 1
4 6 2

ans is 121 & 462

Is this solution Helpfull? Yes (1) | No   

vaibhav singh  (10 years ago)

462
Last digit is square root of first digit
And second digit is the sum of first and last

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Hanamanthappa Kuri  (10 years ago)

let first term be x and last term be squareroot of x then middle term is (x)+ root(x). Then that 3 digit no must be 121 or 462

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thangamani  (10 years ago)

462 and 121

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ritwik verma  (10 years ago)

either 121 or 462

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prabha  (10 years ago)

462
last digit=square root 4
second digit=4+2=6
so,ans 462

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megha  (10 years ago)

Its a 3 digit no. So for a square root to be single digit we can consider 3 no.'s 1,4,9 having sq. root 1, 2, 3 respectively.. 9 should not be considererd bcoz sum of first & last digit(9+3=11) will not be single digit.
We are left with 1 & 4.
For 1, no. would be 121(1st digit, sum of 1st & last digit, squareroot of 1st digit)
For 4, it would be 462 similarly
Answer should be either 121 or 462

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ABHISEK MOHANTY  (10 years ago)

As per question third digit may be 1,2,3.
So first digit will be
if last digit is 1-> 1_1,
if last digit is 2-> 4_2,
if last digit is 3-> 9_3.
Given 2nd digit is sum of first and second, Therefore add first and last digit. With this condition last digit as 3 is not satisfied because 9+3 = 12. And condition for last digit 1, 2 satisfies wrt question.
Ans- 121 (last digit sqr(1), second digit = sum of 1st and last i.e, 1+1 = 2)
462 (last digit sqr(4), second digit = sum of 1st and last i.e, 4+2 = 6)

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Ashish Gupta  (10 years ago)

answer will be 462

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Sathish Kumar S  (10 years ago)

001, square root of 0+1 is 1 and sum of 0+1 is 1

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SOUMYA TRIPATHI  (9 years ago)

its 121 & 264

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