Latest Infosys Aptitude Question SOLUTION: Q. In a certain office, 1/3 of the workers are women, 1/2 of the women are married and 1/3 of the married women have children. If 3/4th of the men are married and 2/3rd of the marr

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Q. In a certain office, 1/3 of the workers are women, 1/2 of the women are married and 1/3 of the married women have children. If 3/4th of the men are married and 2/3rd of the married men have children, what part of workers are without children?

Asked In Infosys RagunathKC (10 years ago)

Unsolved Read Solution (16)

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Read Solution (16) :

shoaib  (10 years ago)

ans is : 11/18

Is this solution Helpfull? Yes (20) | No (2)  

Prachi Gupta  (10 years ago)

women=p/3(if total no of workers=p) & men=2p/3
married womn=(p/3)*0.5=p/6 & marrd mn=(2p/3)*(3/4)=p/2
wmn with chld=(p/6)*(1/3)=p/18 & mn with chld=(p/2)*(2/3)=p/3
without chld=p-(p/18+p/3)=11p/18

solved by :- SUBHRAJIT MITRA
therefore ans is=11/18

Is this solution Helpfull? Yes (15) | No   

GANAPATI  (10 years ago)

5/18
bcz totala workers be x:
(1/3)x=women:
so, (2x/3)=men:
(x/6):married_women:(x/2):married men:
(x/18):Women__childrn:(x/3):chill_men:
so,(x/9):Not hv_childr(women) (x/6):Nt_hv_chil_men:
so (x/9)+(x/6)=(5/18)x

Is this solution Helpfull? Yes (6) | No (4)  

ritwik verma  (10 years ago)

let total employees=90
women=30,men=60
married women having children=5
women without children= 30-5=25
married men having children=30
men without children= 30
so part of employees without children= (30+25)/90 = 11/18

Is this solution Helpfull? Yes (5) | No (1)  

megha  (10 years ago)

Here we want to know the part of workers that are without children. If we subtract the total workers from the workers that has children we can get the solution.
let the total workers be x.
total women workers = 1/3 of total workers
= 1/3 of x = 1/3x
total married women = total women workers / total married women
= 1/3x / 1/2=1/6x
total married women having children = total married women / total married women with children = 1/6x / 1/3 = 1/18x

similarly calculate for married men with children = 1/3x
Now workers without children= total workers - (women with children + men with children)
x-(1/18x + 1/3 x)=11/18x
Answer is 11/18

Is this solution Helpfull? Yes (3) | No   

Sreelakshmy  (10 years ago)

women = 1/3 :: Men = 2/3
Married women = 1/6 :: Married men = 1/2
women have children = 1/18 :: Men have children = 1/3
Part of workers without children = 1-(1/18+1/3) = 11/18

Is this solution Helpfull? Yes (3) | No   

narayana  (10 years ago)

consider total strength is x
then women are x/3, married are x/6,in which have children x/18.
rem 2x/3 are men,which x/2 are married,which 2x/6 have child.
so people wthout chldren are x-(x/18)-(2x/6)=11x/18...ans is 11/18

Is this solution Helpfull? Yes (2) | No   

jaya  (10 years ago)

7/18 part of workers are without children

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chifla  (10 years ago)

pls anyone explain the solution..

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Debarshi Saha  (10 years ago)

@ganpati why 5/18 explain

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mansi  (10 years ago)

plz anyone send me the latest elitmus n infosys question papers.

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GANAPATI  (10 years ago)

@SHOAIB how 11/18 would u plz explain???

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SRISHTI PANDEY  (10 years ago)

its : 11/18

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varsha singh  (10 years ago)

11/18 is the correct answer

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sanjeev kumar  (10 years ago)

ans is:-11/18

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Firdous Imam  (10 years ago)

suppose total employee=90 ,women=90*1/3=30,married=30*1/2=15,children=15*1/3=5
men employee=90-30=60,married=60*3/4=45,children=45*2/3=30
so total employee with children=30+5=35
employee wdout children=90-35=55
part of workers wdout children=55/90=11/18

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