Latest Accenture Aptitude Question SOLUTION: Q. My husband\'s watch gains 2 minutes every watch and my watch loses 1 minute for each hour. One day, we were late to marriage because the difference between the time in the two w

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Q. My husband's watch gains 2 minutes every watch and my watch loses 1 minute for each hour. One day, we were late to marriage because the difference between the time in the two watches was 1 hr and we looked at the slow watch. When did we last set our watches to the same time?

Asked In Accenture chandreyee chowdhury (10 years ago)

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prosenjit singha  (10 years ago)

1st hr diff 3min 2nd hr 6min 3rd 9min so ap series 3,6,9,12...... diff 60min 60 is 20th term by applng frula of nth trm a+(n-1)d=60 whre d=3,a=3,n=? so they last set dr wtch before 20hr

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Kiran Notwani   (8 years ago)

Suppose they had set their watches X hours ago.
Husband's watch gains 2X/60 hour every hour while wife's watch loses X/60 every hour.

Now as one watch gains and other loses the difference will be added

Hence (2X/60) + (X/69)= 1 (hour)
Thus X= 20 hours.
Note : If both watches would have gained or if both would have been losing then we would have subtracted the difference.

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Mayank Kumar  (8 years ago)

ans= 20 hrs

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